How to Using tableView model in C++ code with UI in QML

? Offline

Hi everybody;

Who can help me to solved my problem :)
I want show data from database into qml Tableview

How can i create model and show my database data into my qml ui.

main file :

@
QQmlApplicationEngine engine;
MyData data;
engine.rootContext()->setContextProperty("MyData", &data);
engine.load(QUrl(QStringLiteral("qrc:///main.qml")));

@

This is my QML file :

@
TableView {
model: MyData.KZ()
anchors.margins: 12
anchors.fill: parent
TableViewColumn {
role: "id"
title: "ID"
width: 120
}
TableViewColumn {
role: "firstname"
title: "First Name"
width: 120
}
TableViewColumn {
role: "lastname"
title: "Last Name"
width: 120
}
}
@

This is my function in Widget mode :

@
public:
void KZ() {

if (OpenConnection())
{

}

else
{


 QSqlQueryModel * model = new QSqlQueryModel();
 QSqlQuery * query = new QSqlQuery();
 query->prepare("Select doc_number,first_name,last_name from document");
 query->exec&#40;&#41;;

 model->setQuery(*query&#41;;
 ui->tableView_2->setModel(model);
 ui->tableView_2->model()->setHeaderData(0, Qt::Horizontal, QObject::tr("ID"));
 ui->tableView_2->model()->setHeaderData(1, Qt::Horizontal, QObject::tr("First Name"));
 ui->tableView_2->model()->setHeaderData(2, Qt::Horizontal, QObject::tr("Last Name"));

}

}
@

I need to write again this function for QML..

my function is wrong for qml :

@
public:
Q_INVOKABLE QVariant KZ() {

if (OpenConnection())
{

QSqlQueryModel * model = new QSqlQueryModel();
QSqlQuery * query = new QSqlQuery();
query->prepare("Select doc_number,first_name,last_name from document");
query->exec();
model->setQuery(*query);

 ui->tableView_2->setModel(model);
 ui->tableView_2->model()->setHeaderData(0, Qt::Horizontal, QObject::tr("ID"));
 ui->tableView_2->model()->setHeaderData(1, Qt::Horizontal, QObject::tr("First Name"));
 ui->tableView_2->model()->setHeaderData(2, Qt::Horizontal, QObject::tr("Last Name"));

return .... what ?
}

else
{




}

@

Xander84

I am not sure but you should be able to just use your QSqlQueryModel and set that as the QML TableView model!?
You just need to set QSqlQueryModel as a property or have a getter from QML to c++ to use it.
small example:
@
TableView {
model: cppInterface.getMyModel() // Q_INVOKABLE function of type QSqlQueryModel
...
}
@

? Offline

[quote author="Xander84" date="1399759722"]I am not sure but you should be able to just use your QSqlQueryModel and set that as the QML TableView model!?
You just need to set QSqlQueryModel as a property or have a getter from QML to c++ to use it.
small example:
@
TableView {
model: cppInterface.getMyModel() // Q_INVOKABLE function of type QSqlQueryModel
...
}
@[/quote]

I know Xander84 :) But I want write c++ function to return model for qml table view.

andre

Simply return the QSqlQueryModel instance from a Q_INVOKABLE function. So, what your return in your last snippet in the opening post is model.

? Offline

[quote author="Andre" date="1399882697"]Simply return the QSqlQueryModel instance from a Q_INVOKABLE function. So, what your return in your last snippet in the opening post is model.[/quote]

Thank you for reply ! exactly my problem is return model.
How can I return my model ? I need an example.

Please show me in my function :
of course this is for Q Widget Application.

@
public:
Q_INVOKABLE QVariant KZ() {

if (OpenConnection())
{

QSqlQueryModel * model = new QSqlQueryModel();
QSqlQuery * query = new QSqlQuery();
query->prepare("Select doc_number,first_name,last_name from document");
query->exec();
model->setQuery(*query);

 ui->tableView_2->setModel(model);
 ui->tableView_2->model()->setHeaderData(0, Qt::Horizontal, QObject::tr("ID"));
 ui->tableView_2->model()->setHeaderData(1, Qt::Horizontal, QObject::tr("First Name"));
 ui->tableView_2->model()->setHeaderData(2, Qt::Horizontal, QObject::tr("Last Name"));

return .... what ?
}

else
{




}

@

andre

fill in "model" where you now say ".... what?", and it should work. Notice that the return value of the function can also just be QAbstractItemModel*, instead of QVariant.

? Offline

[quote author="Andre" date="1399883578"]fill in "model" where you now say ".... what?", and it should work. Notice that the return value of the function can also just be QAbstractItemModel*, instead of QVariant.[/quote]

I want say after

model->setQuery(*query);

set model and header thene return this model for qml.

Please Notice to below codes :

@
ui->tableView_2->setModel(model);
ui->tableView_2->model()->setHeaderData(0, Qt::Horizontal, QObject::tr("ID"));
ui->tableView_2->model()->setHeaderData(1, Qt::Horizontal, QObject::tr("First Name"));
ui->tableView_2->model()->setHeaderData(2, Qt::Horizontal, QObject::tr("Last Name"));
@

these are for QWidget application but i want to convert these to qml application ! i need to rewrite there on a function and then return with Q_INVOKABLE to my qml.

My problem is instance of table view model.

andre

Why don't you just delete the parts you no longer need? That is: if you are not using the tableView any more, there is no need to have code to instantiate it.

? Offline

[quote author="Andre" date="1399884232"]Why don't you just delete the parts you no longer need? That is: if you are not using the tableView any more, there is no need to have code to instantiate it.[/quote]

You mean is this code can work alone ?

@
Q_INVOKABLE QVariant KZ() {

    QSqlQueryModel * model = new QSqlQueryModel();
    QSqlQuery * query = new QSqlQuery();
    query->prepare("Select doc_number,first_name,last_name from document");
    query->exec&#40;&#41;;

    return model->query();

}

@

andre

Almost. You want to return model itself, not_ model->query()_;

? Offline

Thank you for your reply
So... Please if you can check my project for help me to solved it :

Check my qml file in line 94 and my kambiz.h file in line : 64

I can't solve this :(

http://www.pal4dream.net/up/do.php?id=1288

andre

No, you'll have to do your own debugging. This forum does not provide a free debugging service.

? Offline

[quote author="Andre" date="1399887061"]No, you'll have to do your own debugging. This forum does not provide a free debugging service.[/quote]

Thank you for helping I try to solve it.