[Solved] Creating QModelIndex from QTableView row number

maximus

I would like to create a QModelIndex from a row number in a QTableView.

I know you can get the row from the QModelIndex (index.row())
I'm wondering if you can go the opposite way?
Reason I need a QModelIndex is that i'm drawing a custom QWidget on top of a QTableView and I need the function "visualRect(QModelIndex)" of QTableView in order to find the position on the screen.

I tried adding a custom method in my QAbstractTableModel like this:
@QModelIndex IntervalTableModel::getIndexAtRow(int row) {

qDebug() << "getIndexAtRow";
QModelIndex index(row, 0); // not valid constructor..
return index;

}@

I would use this code from the main file here :
@
void WorkoutCreator::restoreRepeatWidgetInterface()
{

foreach (RepeatWidget *wid, lstRepeatWidget)
{
    int firstRow = wid->firstRow;
    int lastRow = wid->lastRow;

    QModelIndex firstIndex =  intervalModel->getIndexAtRow(wid->firstRow);

    /// TODO: redraw widget on top of QTableView
}

}
@

Thanks last post for a while sorry for all the posts ;)

maximus

Solved, it was explained in the docs :
I will try this

To obtain a model index that refers to an existing item in a model, call QAbstractItemModel::index() with the required row and column values, and the model index of the parent. When referring to top-level items in a model, supply QModelIndex() as the parent index.