[SOLVED] About showing QWindow

madoodia

hi guys
i am working on a project that use PyQt5 and QML.
i have this two files and they work:
PyQt file:
@import sys
from PyQt5.QtCore import QUrl
from PyQt5.QtWidgets import QApplication
from PyQt5.QtQuick import QQuickView

app = QApplication(sys.argv)

view = QQuickView()
view.setSource(QUrl("example.qml"))
view.show()

sys.exit(app.exec_())@

and QML File:

@import QtQuick 2.0

Item {
id: root
width: 300; height: 100

Rectangle {
id: bg
anchors.fill: parent
color: "red"

 Text {
     id: helloworld
     text: "Hello world!"
     anchors.centerIn: parent
     color: "White"
     font.pointSize: 20
 }

}
}@

this project work.
but question here:
if instead of Item type that is instanced from QQuickItem, i use ApplicationWindow that instanced from QWindow, QQuickView can not show the window for me.
i want to know that what Class of QtQuick should i use to show ApplicationWindow from PyQt?

PyQt File: (same as before)
@import sys
from PyQt5.QtCore import QUrl
from PyQt5.QtWidgets import QApplication
from PyQt5.QtQuick import QQuickView

app = QApplication(sys.argv)

view = QQuickView()
view.setSource(QUrl("example.qml"))
view.show()

sys.exit(app.exec_())@

QML File:

@import QtQuick 2.0
import QtQuick.Controls 1.0

ApplicationWindow {
id: root
width: 300; height: 100
title: "my window"

Rectangle {
id: bg
anchors.fill: parent
color: "red"

 Text {
     id: helloworld
     text: "Hello world!"
     anchors.centerIn: parent
     color: "White"
     font.pointSize: 20
 }

}
}@

the error is : QQuickView only supports loading of root objects that derive from QQuickItem.

thanks in advance

Xander84

Hi, if you want to use an QML ApplicationWindow as the root element you can't use QQuickView. I don't know if there is any official example for it but I can show you I use it in my app, this is c++ though, but I think you can easily convert it to Python:
@
QQmlApplicationEngine engine(QUrl("qrc:///main.qml"));
QObject *topLevel = engine.rootObjects().value(0);
QQuickWindow window = qobject_cast<QQuickWindow>(topLevel);
window->show();
@
so you have to create the QQmlApplicationEngine yourself and just pass it your QML file containing the ApplicationWindow.
That is at least how I use it. :)

madoodia

Thanks
i try to change it to python
but i don't know how change this line to it:
@QQuickWindow window = qobject_cast<QQuickWindow>(topLevel);@

because python don't have pointer..

Xander84

I have no experience with Python, but since it is a scripting language I guess you can just ignore that part and call the "show" function, try this:
@
engine = QQmlApplicationEngine(QUrl("qrc:///main.qml"))
window = engine.rootObjects().value(0)
window.show()
@
( this is my first "phython" script so I have no idea if that is valid code, just used your code as example haha)

madoodia

oh , yes.
i don't know that line but as you said i ignore it and this code works in PyQt:
@import sys
from PyQt5.QtCore import QUrl
from PyQt5.QtGui import QGuiApplication
from PyQt5.QtQml import QQmlApplicationEngine

app = QGuiApplication(sys.argv)

engine = QQmlApplicationEngine(QUrl("example.qml"))
window = engine.rootObjects()[0]
window.show()

sys.exit(app.exec_())@

really thanks dear Xandar