[SOLVED] Signal generation inside function
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Hi,
I want to generate a signal inside a function. BUT the catch is that the name of the signal depends on the arguments passed to the function.
How can I acheive that.
For example the following function would generate
if id==1.... then@void MainWindow::startButtonsHandling(int id){
QString name_StartSingle("start_signal_%1"); connect(this, SIGNAL(start_signal_1()),plugNPlay,SLOT(pulses_go1()));}@
if id was 2 we would have start_signal_2() and pulses_go2()
Usually I use the findchild function but in this case...?
thanks for your help.
Will I need to pass an argument to the signal and slots instead?
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Hi, seems that you have misunderstanded the function of QObject::connect().
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ok... and by that you mean?
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The signals must be defined in the header of the class.
If you have:
@
// emitter class
signals:
void start_signal_1();
void start_signal_2();
void start_signal_3();
void start_signal_4();// some other class accepting the slots...
private slots:
void pulse_go1();
void pulse_go2();
void pulse_go3();
void pulse_go4();
@why not just switch /case?
@
void MainWindow::startButtonsHandling(int id)
{
switch (id){
case 0:
connect(this, SIGNAL(start_signal_1()),plugNPlay,SLOT(pulses_go1()));
break;
case 1:
connect(this, SIGNAL(start_signal_2()),plugNPlay,SLOT(pulses_go2()));
break;
case 2:
connect(this, SIGNAL(start_signal_3()),plugNPlay,SLOT(pulses_go3()));
break;
case 3:
connect(this, SIGNAL(start_signal_3()),plugNPlay,SLOT(pulses_go3()));
break;
}
}
@Rather messy, but it would work. I believe the signals and slots must be predefined for usage.
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why would you only want to connect one signal? why not connect them all? and just activate the one the id matches?
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Yes this is what I did,
I did not use a switch because that makes the coding dependant on the number of "id" I have.
What I did is connected them all and sent them to a function using signalMapper that returns the "id" of the channel. That function then start the corresponding funciton.
Thanks for your help
