Qml variant to custom QtObject

antonio

I have 2 different C++ objects using Q_PROPERTY and Q_INVOKABLE for a function, in my qml file I have this:

@
include MyObject 1.0 //from c++
incluce MyInvokable 1.0 //from c++

property variant myVariant

MyObject{
id:myObject
}

MyInvokable{
id: myInvokable
}
onCallFunction:{
myVariant = myObject;
myInvocable.invokableFunction( myVariant )
}@

At MyInvokable function I can't get the value of MyObject:

@
void MyInvocable::invocableFunction(QVariant variant)
{
MyObject myObject = qvariant_cast<MyObject>(variant) ; //cant convert to MyObject
qDebug() << "foo: " << myObject.foo();
}
@

MyObject has the macro
@Q_DECLARE_METATYPE(MyObject);@

How can I convert QVariant to my custom Object ?

Regards

beemaster

You don't need to convert from QVariant, try to work with QObject* pointers.
@
void MyInvocable::invocableFunction(QObject* object)
{
MyObject* myObject = static_cast<MyObject*>(object);
qDebug() << "foo: " << myObject->foo(); // pointers!
}
@

tzander

I agree with beemaster, just that I would replace that static_cast with a much more safe qobject_cast.

tzander

Reading your qml, you use a variant there too. Its almost never useful to have a variant in QML, since QML is typesafe. In this case you don't need that property in the first place, but otherwise you should consider using the QtObject type instead;

antonio

Thanks beemaster, Thomas Zander I have taken your advices and now my program works.