[SOLVED]QTimer locks my app

[b1gsnak3]

I have something like this:

@
QToolButton *bla = new QToolButton();
QPropertyAnimation *anim = new QPropertyAnimation(this, "geometry");
anim->setDuration(300);
anim->setvalues(...) //bla bla not important
anim->start();
QTimer timer;
timer.start(5000);
bla->setDisabled(true);
while(timer.isActive()) {}
buzzButton->setEnabled(true);
@

this is a basic snippet from my actual code... But I am pretty sure that it is from the timer. Because if I don't add it it goes perfectly.
Thank you in advance

Qt 4.8.4. MSVC2008 (Windows 7 x86)

[andre]

Why are you introducing a busy waiting loop then?
Instead, just connect the timeout signal of the timer to the setEnabled slot of the buzzButton

[qxoz]

I guess not timer locks your app
change code it like this:
@while(timer.isActive())
{
qApp->processEvents(QEventLoop::ExcludeUserInputEvents);
}
@

[qxoz]

[quote author="Andre" date="1359620982"]Instead, just connect the timeout signal of the timer to the setEnabled slot of the buzzButton[/quote]
It depends from goals. If b1gsnak3 need a function which should return some value after finishing his work then busy waiting loop is applicable, but for other ways ofcourse timeout timer is more prefered.

[andre]

[quote author="qxoz" date="1359621458"]If b1gsnak3 need a function which should return some value after finishing his work then busy waiting loop is applicable, but for other ways ofcourse timeout timer is more prefered.
[/quote]

In my opinion, busy looping in a GUI thread is (almost) never acceptable. I don't think promoting it is a good idea.

[qxoz]

I am agree with you, but, what alternative can be used in function like this?:
@QString getRemoteId(QString login, QString pass);@
function should connect with server via tcp and return result to main programm.

[andre]

You'd replace it by an asynchronous call. Especially since the above may fail in all kinds of ways. Look to [[doc:QNetworkAccessManager]] for one possible implementation, and to [[doc:QFuture]] for another one.

[qxoz]

Thanks Andre :)

[b1gsnak3]

Thank you I solved using the timeout signal.