[Solved] How to make Ui read from a file and display it

[pragati]

Hi All,

I am trying to fetch some data from a file and display it on a label or a say line edit

Now if I try it in the following way that is create a label from code and then apply the logic it runs fine but if I try same logic on a ui made from a designer then it gives error.

Code snippet which is working fine is:

@

#include <QFile>
#include <QApplication>
#include <QLabel>
#include <QString>
#include <QTextStream>
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
QFile file("/home/pragati/in.txt");
file.open(QIODevice::ReadOnly | QIODevice::Text);

QTextStream in(&file);
QString line = in.readLine();

QLabel label(line);
label.show();

return app.exec();
}
@

But the same thing i do in the following way :
@

#include "widget.h"
#include "ui_widget.h"
#include <QFile>
#include <QApplication>
#include <QLabel>
#include <QString>
#include <QTextStream>

Widget::Widget(QWidget *parent) :
QWidget(parent),
ui(new Ui::Widget)
{
ui->setupUi(this);
QFile file("/home/pragati/in.txt");
file.open(QIODevice::ReadOnly | QIODevice::Text);
QTextStream in(&file);
QString line = in.readLine();
ui->label(line);

}

Widget::~Widget()
{
delete ui;
}
@

It gives the error : /home/pragati/FIleRead/widget.cpp:18: error: '((Widget*)this)->Widget::ui->Ui::Widget::<anonymous>.Ui_Widget::label' cannot be used as a function

I know there must be some other way. Please anyone can help me in this.....

Thanks a ton in advance

[pragati]

Should I use a signal and slot to make use that function?

[Sam]

You can set the text like

@ui->label->setText(line);@

[pragati]

Whoww......How could I miss something like that....I am so grateful to you for pointing out the silliest thing I forgot.....Thanks a lot Sam!!!

[Sam]

You are welcome .

[pragati]

:)

[Sam]

Kindly Edit the title and add [Solved] to it.

Happy Coding :)