QML does not see httprequest.readyState

shokarta

hello...
so scenario:

property var xmlrequest = new XMLHttpRequest()

function triggerRequest() {
    xmlrequest.abort();		// cancel old call if any
    xmlrequest.onreadystatechange() {
        console.log("readystateChanged to:", xmlrequest.readyState);    // properly print 1, then 2, then 3, then 4
    }
    MODEL.feed_xmlhttp.onload = function() {
        console.log("loaded, so status should be 4", xmlrequest.readyState); // properly debugs 4
    }
    xmlrequest.open("GET", some_url, true);
    xmlrequest.send();
}

function doSomething() {
    console.log("triggered");
}
property bool checkIfIsFinishedProcessing: xmlrequest.readyState
onCheckIfIsFinishedProcessingChanged: if (xmlrequest.readyState == 4) { doSomething(); }  // this does nothing (XMLHttpRequest.DONE also does not work, === operator for both (4 and DONE) also dont)
onCheckIfIsFinishedProcessingChanged: console.log(typeof xmlrequest.readyState, xmlrequest.readyState)  // properly debugs "number" as type, and then 1, 2, 3, 4 as it changes...

so what do I do wrong here?

Axel Spoerl

Please read the documentation about the XMLHttpRequest type.

The important part is:
Assign a callback function to the onreadystatechange signal handler.

More specifically, readyState doesn't have a change signal. Furthermore, the (redundant) binding to checkIfIsFinishedProcessing is crippled. If it would work at all, it would bind an enumeration to a boolean. Comparing the result to the int value 4, is also not a recommended practive. Better use the enum value Done for better code readability.

shokarta

So can i link my qml variable outside of that JS function to the onreadystatechange so once it changes it triggers something im qml?

Axel Spoerl

I am not sure, what your question exactly means.
You have to implement a function and register it as the callback function for state changes.
Totally up to you, what that function does/triggers/changes/debugs.