'emit' in 'pyqtSignal not find

Yattara

Cannot find reference 'emit' in 'pyqtSignal | pyqtSignal'

Hello everyone, can anyone help me understand this problem?

SGaist

Hi,

Without the code triggering the message, no.

Yattara

@SGaist
Here is the code

import sys
from PyQt6.QtWidgets import *
from PyQt6.QtCore import pyqtSignal

class FenetreSimple(QWidget):
simpleSignal = pyqtSignal()
signalAvance = pyqtSignal(int, list, str)

def __init__(self, parent=None):
    super(FenetreSimple, self).__init__(parent)
    self.edition = None
    self.editionCopie = None
    self.fermer = None
    self.disposition = None
    self.execute()

def execute(self):
    self.resize(250, 300)
    self.move(500, 200)

    self.edition = QLineEdit()
    self.disposition.addWidget(self.edition)

    self.editionCopie = QLineEdit()
    self.disposition.addWidget(self.editionCopie)

    self.edition.textChanged.connect(self.exempleSlot)

    self.setLayout(self.disposition)

def boutonSlot(self, checked=False):
    self.simpleSignal.emit(2, [1, 2, 3], 'Hello')

def slotAvance(self, *args):
    print("I am a simple slot")
    print(args[0])
    print(args[2])

    self.show()

if name == 'main':
application = QApplication(sys.argv)
fenetre = FenetreSimple()
sys.exit(application.exec())

SGaist

Why are you mixing PySide6 and PyQt6 ?

Yattara

@SGaist
I uninstalled pyside6, but the problem persists

JonB

@Yattara said in 'emit' in 'pyqtSignal not find:

simpleSignal = pyqtSignal()
signalAvance = pyqtSignal(int, list, str)
self.simpleSignal.emit(2, [1, 2, 3], 'Hello')

Although the error message sounds surprising, try calling the correct signal for the parameters you pass and see if it changes?

Otherwise please copy and paste the error message and confirm the line number it is on.

Yattara

@JonB
Thank you, I corrected this error, but the problem still persists

SGaist

@Yattara Next time please ensure that your example really allows to reproduce your issue. Here boutonSlot will never be called because it's not called from anywhere. Also, your FenetreSimple widget is never shown.

Anyway, here is a small example that works with a complex signal.

import sys

from PyQt6.QtWidgets import QApplication
from PyQt6.QtWidgets import QPushButton
from PyQt6.QtWidgets import QHBoxLayout
from PyQt6.QtWidgets import QWidget
from PyQt6.QtCore import pyqtSignal

class Widget(QWidget):
    complex_signal = pyqtSignal(int, list, str)

    def __init__(self, parent=None):
        super().__init__(parent)

        button = QPushButton("Test me")
        layout = QHBoxLayout(self)
        layout.addWidget(button)

        button.clicked.connect(self.on_clicked)
        self.complex_signal.connect(self.on_complex_signal)

    def on_clicked(self, checked=False):
        self.complex_signal.emit(2, [1, 2, 3], 'Hello')

    def on_complex_signal(self, *args):
        for idx, item in enumerate(args):
            print(idx, item)


if __name__ == '__main__':
    application = QApplication(sys.argv)
    widget = Widget()
    widget.show()
    sys.exit(application.exec())