Execute a python script stored in qrc file

[Renio]

Good evening,
in my qt application I would like to run a python script through this code:

void SandboxDialog::onExecPythonClicked(void)
{

    QStringList params;
    params << ":/file/PythonSandboxClass.py";
    moP.start("python3", params);
    moP.waitForFinished();

    ui->moTextEdit->append("calling  PythonSandboxClass.py");
}

the python file is placed in a python .qrc file

<RCC>
    <qresource prefix="/file">
        <file>PythonSandboxClass.py</file>
    </qresource>
</RCC>

but when I run the application, I get the following error:

/usr/bin/python3: can't open file '/home/Qt/DiagSendbox/bin/:/PythonSandboxClass.py': [Errno 2] No such file or directory

My questions are:

• in the qrc file can I load files with *.py extension
• if yes, where am I wrong?

[JonB]

@Renio
Resources are placed physically within the executable file. Qt code can access them via :/... syntax, but nothing outside can, they are not files in the operating system.

To do what you want you would need to extract that file to an external .py file, get python3 to execute that, and finally delete the file.

[Renio]

@JonB Thank you for your reply.
I do this because I don't want insert the path of python file into my code, or avoid that someone replace my script.
this is my pro file

QT       += core gui

greaterThan(QT_MAJOR_VERSION, 4): QT += widgets

CONFIG += c++11

# You can make your code fail to compile if it uses deprecated APIs.
# In order to do so, uncomment the following line.
#DEFINES += QT_DISABLE_DEPRECATED_BEFORE=0x060000    # disables all the APIs deprecated before Qt 6.0.0

SOURCES += \
    main.cpp \
    SandboxDialog.cpp

HEADERS += \
    SandboxDialog.h

FORMS += \
    SandboxDialog.ui

TRANSLATIONS += \
    DiagSendbox_it_IT.ts
CONFIG += lrelease

# Default rules for deployment.
qnx: target.path = /tmp/$${TARGET}/bin
else: unix:!android: target.path = /opt/$${TARGET}/bin
!isEmpty(target.path): INSTALLS += target

DISTFILES += \
    PythonSandboxClass.py

RESOURCES += \
    python.qrc

I undestrud that i can't to do this, correct?

[JonB]

@Renio
Sorry, I don't understand if there is a further question here. This is fine, I wrote in my previous why you get the error trying to execute it and what you need to do at runtime to make it work.