C++ QWidget class has no member (n)

[Pekoyo]

Good day!

I'm having the following problem:

I have a custom class named WidgetStyle, inheriting from a QWidget.
WidgetStyle has a std::string variable called MY_Style, which stores custom information

I add a lot of these items to a layout and have to iterate through them and get the variable MY_Style stored in them.

for (int i = 0; i < MyLayout->count(); i++) {
         MyLayout->itemAt(i)->widget()->MY_Style
}

C++ returns the error : "class QWidget has no member MY_Style"

, which if they were normal qwidgets they wouldn't have that member, but how do I indicate to c++/QT that the items in the layout are not QWidgets but instead my inherited WidgetStyles that do have that property/member?

Thank you!

[JonB]

@Pekoyo
As @Kent-Dorfman says. To that end have a look at qobject_cast<>().

[Kent-Dorfman]

you need to research and learn c++ casts...and related, the use of virtuals.

widget() is probly returning a qwidget* as its type, so it wont' understand an implicit cast to the subclass.

[JonB]

@Pekoyo
As @Kent-Dorfman says. To that end have a look at qobject_cast<>().

[Pekoyo]

@Pekoyo Thanks for all the answers: here is my solution if it helps anyone

in my class WidgetStyle simply add

struct WidgetStyle: QWidget {
    Q_OBJECT
public:
    WidgetStyle();
};

qobject_cast<WidgetStyle* >(MYLayout->itemAt(i)->widget())->MY_Style