QRegularExpression

[Morgatte]

Hi,

I would like to extract some QString

            /* My QString = "Lu 01/10/2023;2.60 m;4h16B;8h27M;16h46B;21h02M" */
            static const QRegularExpression re("\\d.\\d{1,2}");
            QRegularExpressionMatch match = re.match(ligne1);
            qDebug() << re.pattern();

            if (match.hasMatch()) {
                a = match.captured(1);     // 2.60
            }


            qDebug() << "a =" << a;

            exit(0);

even if I use re("\d.");
or re("^\d$"); or anything else, nothing works.

I do not anderstand.

[JonB]

@Morgatte
What is it you want but don't get?? Your question is not clear. Do you get 2.60 or do you want 2.60 but not get it? I would assume it would match the 1/10 which comes early in the string? Or maybe 2023 if captured(1) is the second match. Actually you have no capturing groups, so I'm not sure captured(1) would ever return anything.

Could you please actually qDebug() << ligne, and could you state whether it goes into the if (does it match? how many captures are in it?) and could you show the output from qDebug() << "a =" << a;. You can see the output, we cannot, we are not mind readers!

In any case, since you intend your reg ex to capture a literal . between the digits I assume it should read

"\\d\\.\\d{1,2}"

[Morgatte]

thanks,

I forgiven It.
I used a simple

.indexOf()
.mid()

That works.

[JonB]

@Morgatte Fine, well, QRegularExpression works OK so I don't know what you were expecting.