Passing QScopedPointer to a member object

[ODБOï]

Hello,

Is it possible to pass /share a member QScopedPointer to another member object ?

example :

class myClass : public QObject
{
public :
// ctor
 explicit myClass (QObject *parent = nullptr){
  handler = new CommunicationHandler; 
  handler->setClient(&myClient);  // is this possible ? how to implement the "setClient()" method in  CommunicationHandler  pls ?
}
private :
 CommunicationHandler *handler;  
 QScopedPointer<QOpcUaClient> myClient;
}

thank you

[Christian Ehrlicher]

QScopedPointer has a data() function. Or use a shared pointer or non at all (in this case I don'T see a reason to use one and your example passes an empty pointer so nothing will happen). Passing a pointer to a QScopedPointer is really bad design.

[ODБOï]

@Christian-Ehrlicher hi
Thank you very much for your answer.

this works as i expect, but are you saying this is bad design ?

  //CommunicationHandler  class,  needs  a pointer to  QOpcUaClient 
       QOpcUaClient* m_uaClient;           
        void setUaClient(QOpcUaClient *uaClient){
                m_uaClient = uaClient;    
        }

// base class where  CommunicationHandler   is created
protected: 
 QScopedPointer<QOpcUaClient> m_client;
    [...]
{
 handler = new CommunicationHandler; 
 handler->setUaClient(m_client.data());
}

[Christian Ehrlicher]

@LeLev said in Passing QScopedPointer to a member object:

but are you saying this is bad design ?

no, I did not say that this is bad design.

[ODБOï]

@Christian-Ehrlicher
ok good. Thanks