QString(" %1 of %2").arg(...); whats happening?

SPlatten

I am trying to format 1 or N into a string with:

quint16 uint16Part = 1, uint16Parts = 2;
QString strOutput("    Debug:");
strOutput += QString(" %1 of %2").arg(uint16Part, uint16Parts);

The values assigned above are just for demonstration purposes. What I see in strOutput after the last operation is:

"   Debug:                                    1 of %2"

Why? I was expecting:

"  Debug: 1 of 2"

SPlatten

Solved, changing to:

strOutput += QString(" %1 of %2").arg(uint16Part).arg(uint16Parts);

ODБOï

@SPlatten hi
you can do

strOutput += QString("%1 of %2").arg(uint16Part).arg(uint16Parts);

SPlatten

@LeLev , thank you, I must have been typing my own response whilst you were.

HoMa

on the "why": the variants of arg(...) with an int as second argument assume this to be the field width into which the first argument should be fitted into.
For multiple replacements you need all arguments to be QStrings.
Check the documentation: https://doc.qt.io/qt-5/qstring.html#arg-3

Regards
Holger

SPlatten

Not sure where is states that and it doesn't work.