How to use dynamic path to read file on FileDialog open
-
Hi All,
I have a menubutton in qml which open FileDialog on clicked , i need to set path to default folder which i have created as import :
Sample code as fallowsMenuButton {
label: qsTr("Import")imageSource: "qrc:/images/abc.svg" onMenuButtonClicked: //Open file browser to choose file { openFileDialog.open(); } }
FileDialog{
id:openFileDialog
title: "Please choose a file"
folder: "file:///C:/Users/Documents/gui/Import" //need to set dynamic pathonAccepted: { selectedFilePath = folder model.readPointsFromFile(selectedFilePath) }
tried setting folder: "file:///" + applicationDirPath + /gui/Import" did not work
Thanks :)
-
Please use code tags around code, it's easier to read.
tried setting folder: "file:///" + applicationDirPath + /gui/Import" did not work
How do you define
applicationDirPath
? Does QML print any warnings? -
Hi @sush123 ,i guess you need to set "folder" path of fileDialog
here is a sample code, in which i set 3 different folder paths please have look into.If iam wrong with my understanding please do correct me.
//Use this variable to set the path of the folder, change it according to your path property string folderPath: "C:/DummyFolder" property int index: -1 FileDialog { id: fileDialog title: "Please choose a file" onAccepted: { console.log("You chose: " + fileDialog.fileUrls) fileDialog.close() } onRejected: { console.log("Canceled") fileDialog.close() } } Button { id: changeButton text: "Open" onClicked: { //You can set the path of the folderPath here also // folderPath = "C:/DummyFolder1/Images" etc etc if(parent.index > 2) parent.index = -1; parent.index++; switch(parent.index) { case 0: fileDialog.folder = fileDialog.shortcuts.documents break; case 1: fileDialog.folder = fileDialog.shortcuts.desktop break; case 2: fileDialog.folder = "file:///" + parent.folderPath break; } fileDialog.open() } }