QGroupBox, QCheckBox, select several options.

lincoln

Hi guys, I have this code, in my form I have two QGroupBox with different alternatives, as you can see in the code what I try to show in a message the options that the user chose, but when I click on my button the program simply closes .

Here my code.

#ifndef GROUPBOXDIALOG_H
#define GROUPBOXDIALOG_H

#include <QDialog>
#include <QMessageBox>
#include <QGroupBox>

namespace Ui {
  class GroupBoxDialog;
}

class GroupBoxDialog : public QDialog
{
  Q_OBJECT

public:
  explicit GroupBoxDialog(QWidget *parent = nullptr);
  ~GroupBoxDialog();

private slots:
  void on_buttonBox_accepted();

  void on_buttonBox_rejected();



private:
  Ui::GroupBoxDialog *ui;
  QString getOptions(QGroupBox *group);
};

#endif // GROUPBOXDIALOG_H

#include "groupboxdialog.h"
#include "ui_groupboxdialog.h"

GroupBoxDialog::GroupBoxDialog(QWidget *parent) :
  QDialog(parent),
  ui(new Ui::GroupBoxDialog)
{
  ui->setupUi(this);
}

GroupBoxDialog::~GroupBoxDialog()
{
  delete ui;
}

void GroupBoxDialog::on_buttonBox_accepted()
{
  QString message;

  QString food=getOptions(ui->groupBox_3);
  message.append(food);

  QString activities=getOptions(ui->groupBox_4);
  message.append(activities);

  QMessageBox::information(this,"Details",message);
  accept();
}

void GroupBoxDialog::on_buttonBox_rejected()
{
  reject();
}

QString GroupBoxDialog::getOptions(QGroupBox *group)
{
  QString value;
  foreach(QObject *object, group->children())
    {
      QCheckBox *chk=qobject_cast<QCheckBox*>(object);
      if(chk) continue;
      if(chk->isChecked()) value.append(chk->text()+"\r\n");
    }
  return value;
}

When the application closes, it shows me this message.

my form:

Christian Ehrlicher

@lincoln said in QGroupBox, QCheckBox, select several options.:

when I click on my button

Which button?

JonB

@lincoln
Apart from what @Christian-Ehrlicher has asked you....

Have you attached the two slots in your ui->setupUi(this);?

I assume so. Then you are crashing on if(chk->isChecked()) because of this line:

if(chk) continue;

You mean if(!chk) continue;!

lincoln

thanks, I already solved the problem, it was just changing the condition in the if as jonB said.