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Converting void pointer to qstring

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  • K Offline
    K Offline
    kitten
    wrote on last edited by
    #1

    hi to everyone
    i have a void pointer(argv) and i have a counter of its elements(argc)
    i use this code to parse it and turn it to qstring, this is one of functions of testcon application
    it compiled successfully
    but when i ran a programm it hang
    what is its problem?
    @String paramlist;
    VARIANT params = (VARIANT)argv;
    for (int a = argc-1; a >= 0; --a) {
    if (a == argc-1)
    paramlist = QLatin1String(" - {");
    QVariant qvar = VARIANTToQVariant(params[a], 0);
    paramlist += QLatin1String(" ") + qvar.toString();
    if (a > 0)
    paramlist += QLatin1String(",");
    else
    paramlist += QLatin1String(" ");
    }
    if (argc)
    paramlist += QLatin1String("}");@

    www.kitten.mihanblog.com

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    • sierdzioS Online
      sierdzioS Online
      sierdzio
      Moderators
      wrote on last edited by
      #2

      as a side note, you can use "qApp->arguments()":http://developer.qt.nokia.com/doc/qt-4.7/qcoreapplication.html to get an already parsed QStringList of arguments.

      (Z(:^

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      • K Offline
        K Offline
        kitten
        wrote on last edited by
        #3

        no , the function is'nt my main function
        it is another function

        www.kitten.mihanblog.com

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        • sierdzioS Online
          sierdzioS Online
          sierdzio
          Moderators
          wrote on last edited by
          #4

          the qApp pointer is globally accessible.

          (Z(:^

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          • K Offline
            K Offline
            kitten
            wrote on last edited by
            #5

            i know the qapp pointer is globally accessible but argv and argc is'nt argumens of my main functions
            i should write my code like this to more understand:
            @void func(const QString &gg,int argc,void *argv)
            {
            String paramlist;
            VARIANT params = (VARIANT)argv;
            for (int a = argc-1; a >= 0; --a) {
            if (a == argc-1)
            paramlist = QLatin1String(" - {");
            QVariant qvar = VARIANTToQVariant(params[a], 0);
            paramlist += QLatin1String(" ") + qvar.toString();
            if (a > 0)
            paramlist += QLatin1String(",");
            else
            paramlist += QLatin1String(" ");
            }
            if (argc)
            paramlist += QLatin1String("}");
            }@

            www.kitten.mihanblog.com

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            • G Offline
              G Offline
              goetz
              wrote on last edited by
              #6

              How should we know the problem? We do not even know what's behind your void pointer, not to mention what your VARIANT type is nor the VARIANTToQVariant and how it is organized.

              Oh, and your code would be much more readable, if you would use proper indenting. I would not find a bug in that mess either.

              http://www.catb.org/~esr/faqs/smart-questions.html

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              • K Offline
                K Offline
                kitten
                wrote on last edited by
                #7

                i know the void arguments is an integer but it get me error

                www.kitten.mihanblog.com

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                • G Offline
                  G Offline
                  goetz
                  wrote on last edited by
                  #8

                  Bravo! Now we know exceptionally more and can solve your problem...

                  Sorry, for being sarcastic, but do your really expect that we can comment on your problem with that much information you gave us? Did you try yourself using a debugger and stepping through the code?

                  http://www.catb.org/~esr/faqs/smart-questions.html

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                  • G Offline
                    G Offline
                    giesbert
                    wrote on last edited by
                    #9

                    If yoiu areguments are integers, why do you cast them to VARIANT pointers? Are you talking about COM VARIANTS? If yes, it seams, you don't know their structure, they are not integers.

                    Nokia Certified Qt Specialist.
                    Programming Is Like Sex: One mistake and you have to support it for the rest of your life. (Michael Sinz)

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                    • K Offline
                      K Offline
                      kitten
                      wrote on last edited by
                      #10

                      yes it is a com variants
                      what should i do?

                      www.kitten.mihanblog.com

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                      • G Offline
                        G Offline
                        giesbert
                        wrote on last edited by
                        #11

                        That depends.
                        I have no idea how your input looks like.,
                        If it is ints, don't cast them to VARIANT!

                        Nokia Certified Qt Specialist.
                        Programming Is Like Sex: One mistake and you have to support it for the rest of your life. (Michael Sinz)

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                        • A Offline
                          A Offline
                          andre
                          wrote on last edited by
                          #12

                          You can only savely cast to a known data structure. If you don't have access to that structure (for instance by including a header describing the structure), there is no save way to cast to anything. So: find out what the input data is, and how it is represented. Only then start thinking about casting to it.

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                          • K Offline
                            K Offline
                            kitten
                            wrote on last edited by
                            #13

                            the documentation says it is a integer but
                            for example when it should send me 99 it get me 206
                            and when it should send me 200 it get me 63
                            i don't know what does it mean

                            www.kitten.mihanblog.com

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                            • G Offline
                              G Offline
                              giesbert
                              wrote on last edited by
                              #14

                              We have no idea which program sends you messages and how to interpret them.
                              Contact the one who wrote it.

                              Nokia Certified Qt Specialist.
                              Programming Is Like Sex: One mistake and you have to support it for the rest of your life. (Michael Sinz)

                              1 Reply Last reply
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