Connect trigger() from a QMenu to another function

Dummie1138

Hi. I'm trying to connect trigger() from a QMenu to another function. This is the code.

MenuBar::MenuBar(QWidget *parent) : QWidget(parent){
    resize(800, 20);
    QMenuBar *menuBar = new QMenuBar(this);
    qDebug() << menuBar->size();
    setSizePolicy(QSizePolicy::Fixed, QSizePolicy::Fixed);
    QMenu *menuSettings = new QMenu("Settings", menuBar);
    menuBar->addMenu(menuSettings);

    QMenu *menuExit = new QMenu("Exit", menuSettings);
    menuSettings->addMenu(menuExit);
    connect(menuExit, QMenu::triggered(), this, [=](){this->onMenuExitTriggered();}); //THE IMPORTANT BIT
}

void MenuBar::onMenuExitTriggered(){
    qDebug() << "Exit";
}

On the connect line, the IDE is telling me I am calling a non-static member function with an object argument. This makes sense, since according to the QMenu documentation a QAction needs to be provided as the argument. However I am unsure how to represent this argument in syntax.

Some of the code I have tried:

connect(menuExit, QMenu::triggered(QAction::triggered()), this, [=](){this->onMenuExitTriggered();});

(This is calling a non-static member function with an object argument, despite QAction's triggered not requiring an object argument, which is confusing me)

    QAction *actionExit = new QAction(menuExit);

    connect(actionExit, &QAction::triggered, this, [=](){this->onMenuExitTriggered();});

(There are no syntax issues but I am unsure how to make the QAction a child of the QMenu menuExit)

Please let me know if more info is required.

JonB

@Dummie1138 said in Connect trigger() from a QMenu to another function:

connect(actionExit, &QAction::triggered, this, [=](){this->onMenuExitTriggered();});

This is the only syntactically correct one (the QMenu::triggered(...) cannot be right, you will never want the parentheses, this must be the address of a member method like &QAction::triggered, not a call to that method which is what the (...) would do).

IIRC, QAction *QMenu::menuAction() const returns a QMenu's action to use for the connection given a QMenu you have created (like from QMenu *menuExit = new QMenu("Exit", menuSettings)). UPDATE Or QAction *QMenu::addMenu(QMenu *menu) would return the QAction created from menuSettings->addMenu(menuExit).

BTW, the difference between QAction::triggered and QMenu::triggered is that the former can be specified per item/action in a menu with multiple ones whereas the latter fires for any action/item on the menu, and you then have to find out which one if you need to know.

Dummie1138

I have modified the code accordingly based on @JonB.

    connect(menuExit->menuAction(), &QAction::hovered, this, [=](){this->onMenuExitTriggered();});

This works. Thank you very much to Jon for this.