how to connect C++ signal to QML handler

ODБOï

@mzimmers said in how to connect C++ signal to QML handler:

why is it that directly accessing the variable synthName works

Accessing the variable "synthName" in qml will actually invoke the getter function
https://doc.qt.io/qt-5/qtqml-cppintegration-exposecppattributes.html#exposing-properties

mzimmers

@LeLev right, I understand that...I just don't understand why a direct call to the getter didn't work for me.

Pablo J. Rogina

@mzimmers have you checked the QML + C++ integration documentation?
In particular look for using the onUserNameChanged handler.

ODБOï

@mzimmers said in how to connect C++ signal to QML handler:

I just don't understand why a direct call to the getter didn't work for me.

Your getSynthName() is probably not a public slot nor a Q_INVOKABLE marked function, that's why you can't call it from QML ..

By default if you declare a Q_PROPERTY and use "Refactor" option to generate getter/setter/.., the getter is just public:
but the setter is under public slots, so you can call the setter from qml.
If you want to call "getSynthName()" in QML then move it under "public slots". But then :

Label {
   text: getSynthName()

this will not be updated if the value of "synthName" changes in the c++ side, you will always see the initial value of "synthName"

mzimmers

@LeLev said in how to connect C++ signal to QML handler:

this will not refresh, you will always see the initial value of synthName.

OK, so this is what I needed to know. So...a property will update automatically, where a reference to a function will not, right? Thanks, LeLev.

ODБOï

@mzimmers that is true.

ODБOï

@mzimmers hi again,

sorry i misread your initial code.. i did not see that you declare getSynthName() in QML also ..

In this case i would simply do this :

text: issViewModel.synthName !== "" ? issViewModel.synthName : "No Synthesis Loaded"

no need the js function.

mzimmers

Actually, I cleaned that up a little. I have a couple of utility JS functions now:

  function getNoSynthName() {
    var name =  "No Synthesis Loaded"
    return name;
  }
    function getSynthName() {
      var name = issViewModel.synthName
      if (name === "") {
          name = getNoSynthName()
      }
      return name;
  }

This is the only location that uses the function in issViewModel. This allows me to do this in another area:

 StyledButton {
   visible: Utils.getSynthName() !== Utils.getNoSynthName()
...

ODБOï

@mzimmers said in how to connect C++ signal to QML handler:

visible: Utils.getSynthName() !== Utils.getNoSynthName()

This will be evaluated only single time, you can test it and correct me if i'm wrong.

@mzimmers said in how to connect C++ signal to QML handler:

Actually, I cleaned that up a little. I have a couple of utility JS functions now:
function getNoSynthName() {
var name = "No Synthesis Loaded"
return name;
}
function getSynthName() {
var name = issViewModel.synthName
if (name === "") {
name = getNoSynthName()
}
return name;
}

This is the only location that uses the function in issViewModel. This allows me to do this in another area:
StyledButton {
visible: Utils.getSynthName() !== Utils.getNoSynthName()
...

You could replace all that by this single line that will hide the Styled Button button if the synthName == "" . And it will be reevaluated every time synthName changes...

 StyledButton {
    visible:  issViewModel.synthName

mzimmers

@LeLev said in how to connect C++ signal to QML handler:

@mzimmers said in how to connect C++ signal to QML handler:

visible: Utils.getSynthName() !== Utils.getNoSynthName()

This will be evaluated only single time, you can test it and correct me if i'm wrong.

It seems to update. At app startup, the button isn't visible. When I load a synthesis and return to this screen, the button is visible. The nature of the app is such that once something is loaded, it never returns to an "unloaded" state, so I can't fully test this, but it does update (at least once).

@mzimmers said in how to connect C++ signal to QML handler:

Actually, I cleaned that up a little. I have a couple of utility JS functions now:
function getNoSynthName() {
var name = "No Synthesis Loaded"
return name;
}
function getSynthName() {
var name = issViewModel.synthName
if (name === "") {
name = getNoSynthName()
}
return name;
}

This is the only location that uses the function in issViewModel. This allows me to do this in another area:
StyledButton {
visible: Utils.getSynthName() !== Utils.getNoSynthName()
...

You could replace all that by this single line that will hide the Styled Button button if the synthName == "" . And it will be reevaluated every time synthName changes...
 StyledButton {
    visible:  issViewModel.synthName

Not quite. When no synthesis is loaded, I need that value "No Synthesis Loaded" because I use it in two screens.

ODБOï

@mzimmers said in how to connect C++ signal to QML handler:

Not quite. When no synthesis is loaded, I need that value "No Synthesis Loaded" because I use it in two screens.

if you need the functions in other places then use them, but in this particular case when you write

 StyledButton {
   visible: Utils.getSynthName() !== Utils.getNoSynthName()

you are hiding that button if synthName == ""

This does the same, but is much simpler.

StyledButton {
    visible:  issViewModel.synthName

mzimmers

@LeLev I suppose it's a matter of coding taste. I personally don't care to implicitly determine a boolean based on the contents of a string (or any other variable; I prefer the comparison to be made explicitly. More verbose, but (IMO) easier for the new reader to understand. I do appreciate the input, though.

ODБOï

@mzimmers said in how to connect C++ signal to QML handler:

I prefer the comparison to be made explicitly

you can write it in more explicit way, to me this is simpler

StyledButton {
    visible:  issViewModel.synthName != ""

than

StyledButton {
    visible:  Utils.getSynthName() !== Utils.getNoSynthName()

@mzimmers said in how to connect C++ signal to QML handler:

I suppose it's a matter of coding taste.

To me it is not just a mater of taste.
you are calling 2/3 functions where you could just write one simple js expression...

~~Also because one solution will update/refresh dynamically but the other will not~~
[edit] i was wrong here, actually both solution will update, as explained by @GrecKo

GrecKo

@LeLev said in how to connect C++ signal to QML handler:

Also because one solution will update/refresh dynamically but the other will not
visible: issViewModel.synthName != "" // this will update dinamially
visible: Utils.getSynthName() !== Utils.getNoSynthName() // this will not update dinamially.Only evaluated 1 time on component creation

That's incorrect. Both will updated dynamically since the functions are evaluated in QML. Were the functions implemented in C++, the QML would have no way to figure out the properties dependencies but that that's not the case here.