Return pointer-to-member in const method
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@JonB Add a "goto" to make him even more "happy" :-)
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@jsulm
OK, we're nearly there, but we have a wrinkle.I want these two methods to have the same name. So I don't want the
Const
suffix on theconst
one.I am assuming we can do this in C++, because Qt has methods like
QVector
:T & operator[](int i) const T & operator[](int i) const
(I know that's an operator, but I think if I looked around there are other methods which have both
const
& non-const
variants?)So I try:
const int *pointerToMember() const { return &member; } int *pointerToMember() { return const_cast<int*>(pointerToMember()); }
But the second overload gives Creator yellow-triangle clang warning
warning: all paths through this function will call itself
gcc compiles without warning. But when I test at run-time, sure enough, I get infinite recursion: the second overload calls itself, not the first one, and I am foo-barred :(
So.... Qt seems to manage with same-named
const
& non-const
variants. How can I adapt your suggestion, so they use common code yet work as required, please? E.g. is there anything I can write here to make the second overload'spointerToMember()
call the first one, not itself, some "overloadOf
" or something?EDIT
I guess I could do:private: const int *_pointerToMember() const { return &member; } public: const int *pointerToMember() const { return _pointerToMember(); } int *pointerToMember() { return const_cast<int*>(_pointerToMember()); }
Can I do it without that extra dummy method? Neater, and guaranteed [don't start on me with
inline
;-) ] not to have an inefficient extra function call :) -
@JonB It's getting ugly :-)
const int *pointerToMember() const { return &member; } int *pointerToMember() { const MyClass *_this = this; return const_cast<int*>(_this->pointerToMember()); } // Now compiler knows that you want to call const pointerToMember
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@jsulm
Hmm, good one, thanks! Now I have an extra assignment to slow my code down :( ;-)This is indeed fine, and I get it. Nonetheless, final question: is there something in C++ to do with like "overload of" which can pick between the
const
& non-const
variants here? Just because I am interested. You know that when we use Qtconnect()
we can useQOverload<...>::of
to pick desired function overloads, I have a feeling that resolves to some C++ "overload of" statement? But here we are trying to distinguish between signatures which do not differ in parameters, I'm trying to understand whether that can be done? -
const auto value1 = obj->pointerToMember(); // should be const version auto value2 = obj->pointerToMember(); // should be non-const version
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const int *pointerToMember() const { ... } int *pointerToMember() { ... } const auto value1 = obj->pointerToMember(); // should be const version
Nope (but thanks for your interest!), that
const
one steps straight into the second, non-const
variant! (As does the other call too.)I would not expect
const variable = method()
to call theconst
variant of the method, particularly. So far as I know, thatconst
on the variable perfectly allows it to pick any non-const
method, it only chooses to treat the return result asconst
but no other effect. Which is what it does it here. -
Interesting, maybe don't overload then. I tried as reference to see if it makes a difference. No change.
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@jsulm said in Return pointer-to-member in const method:
int *pointerToMember() { const MyClass *_this = this; return const_cast<int*>(_this->pointerToMember()); } // Now compiler knows that you want to call const pointerToMember
I wrote
Now I have an extra assignment to slow my code down :( ;-)
So I adapted, to remove
_this
:int *pointerToMember() { return const_cast<int*>( const_cast<const MyClass *>(this)->pointerToMember() ); }
I prefer yours for readability :)
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I left you for one minute and there's const_cast and goto :P
Getting back to original problem. At first glance you could do something like this:
class Foo { private: std::array<Stuff, 42> data; int indexOf(Key key) const { return /* some lengthy way to determine the index */; }; public: Stuff* get(Key key) { int index = indexOf(key); return (index < 0) ? nullptr : &data[index]; } const Stuff* get(Key key) const { int index = indexOf(key); return (index < 0) ? nullptr : &data[index]; } };
no casts but I would argue that this is a patch work. The solution becomes a lot nicer if you dig into the problem, which is you're trying to pack two things into one getter - a logic to determine if given element is present and retrieving it. Those are two things and they also incur a performance cost (branching) so I'd say design your interface so that the decision about taking the cost or not is left to the user of your class:
class Bar { private: std::array<Stuff, 42> data; public: int indexOf(Key key) const { return /* some lengthy way to determine the index */; }; Stuff& at(int index) { return data[index]; } const Stuff& at(int index) const { return data[index]; } };
Shorter, easier, faster and class doesn't absorb responsibilities it doesn't need to. Also those
at
methods will most definitely get inlined and disappear (inlining is real and super important, don't dismiss it :) )As for the other thing:
const auto value1 = obj->pointerToMember(); // should be const version
auto value2 = obj->pointerToMember(); // should be non-const versionconst or non-const is determined by the constness of the object it is called on, not unrelated variable the result is assigned to, so:
auto value1 = const_obj->pointerToMember(); // const version, auto resolves to const something auto value2 = obj->pointerToMember(); // non-const version, auto resolves to non-const something
Btw. this is a source of a common performance trap with Qt and C++11:
QVector<Stuff> stuff; for (Stuff& foo : stuff) {} //no! calls non-const begin/end and can cause expensive detach()
so people think "oh, I should just add const and it's fine":
for (const Stuff& foo : stuff) {} //no! still calls non-const begin/end
The proper way to do it is:
for (const Stuff& foo : qAsConst(stuff)) {} //ok, calls const begin/end
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@Chris-Kawa said in Return pointer-to-member in const method:
I left you for one minute and there's const_cast and goto :P
That's what happens to fluffy kittens if you turn your back....
Let's pick my one of what (I understand) you suggest:
int indexOf(Key key) const { return /* some lengthy way to determine the index */; }; Stuff& at(int index) { return data[index]; } const Stuff& at(int index) const { return data[index]; }
So, you avoid the problem by making the lookup function return an
int index
. Then you return const/non-constdata[index]
.This breaks my (unspoken) "efficiency" criterion! My lookup marches through the array without an int counter, only with a pointer (it can return
nullptr
on not-found, so no references here), and returns that. You will make me turn that into an index, and then you will turn it back by adding it ontodata
.I am shocked. I was speaking to someone recently in another thread here, and they berated me for the overhead of indexing into arrays, when I said it was "milliseconds" they said "every microsecond counts, in game development, this is not to be ignored". Can you think who that was? :D
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@JonB said:
Can you think who that was? :D
Yup, and I stand by what I said, which was not indexing into an array but indexing into a vector. Huge huge difference.
The int index is just an example. Every case is different and it doesn't have to be an int. It could be an iterator, some hash thingie or whatever is most efficient in your case. Pointer has that nasty proprty of being both index and data at the same time, which causes your problems - you want a const pointy thing and a non-const data thing. One variable can't be both at the same time so that's why I'm suggesting to split them up.
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int indexOf(Key key) const { return /* some lengthy way to determine the index */; };
The problem here is, that function returning
int
does not exhibit the problem! You don't have to worry about returningint
versusconst int
. It's when function returns asomething *
.int method() const
is never a problem, butint *method() const
where it returns a member variable is a problem. So I see I then needconst int *method() const
as well asint *method()
. Once yourindexOf()
returns a pointer into a member variable thingie you end up needing aconst something *indexOf() const
and asomething *indexOf(Key key)
, for a method which does the same thing.Anyways. My head is hurting on this. We may all be saying the same thing in different ways.
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@JonB said in Return pointer-to-member in const method:
The problem here is, that function returning int does not exhibit the problem!
Exactly, it's intentional on my part and that's the point. Don't try to solve an ugly problem. Redesign and untangle dependencies so there is no problem in the first place ;)
int*
is an "index" andint*
points to data. Untangle those roles.Anyways. My head is hurting on this.
I fear I might have accidentally terrorized you into being paranoid about something that will bring you marginal gains and make your code a lot worse to read/maintain. I'd say, just for test, do the duplicated const and non-const methods, measure how much gain are you actually getting, decide if it's worth it and only then proceed or revert. While I care deeply about performance there is a line below which it's just not worth it, as in how much optimizations can you achieve in a finite amount of time and how it reflects on readability and ease of maintenance. I'd just like that line to be lower than it usually is, but it's up to you really. Don't let me pressure you too much. I've been told I can be bossy ;)
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@Chris-Kawa said in Return pointer-to-member in const method:
measure how much gain are you actually getting, decide if it's worth it and only then proceed or revert
Sounds like what I would say :)
While I care deeply about performance
I do, but kinda more just in an algorithmic sense than whether it makes any visible difference to what I'm doing.
Don't let me pressure you too much. I've been told I can be bossy ;)
Not at all! I read your posts with interest, high quality.
This has all revealed something to me which I had not appreciated. I thought
Class::method() const
only guaranteed that it did not alter*this
. I did not expect that, for safety, it also does not allowClass::Member *Class::method() const
. That function does not itself alter*this
, but I do see that it returns a write-pointer intoconst this *
which could later be used to do so. Hence you have to make that return aconst *
if you wantmethod() const
I just was not aware of this.I'm sure there are just pages of C++ specs I could/ought to read up on
const
.... [Actually I think I did so a while ago, I recall it being longggggg.]P.S.
When I started C it didn't haveconst
yet. Lambs gambolled carefree in the fields, life was easy then... -
If you want some further discussion points, take a look at how the Qt api returns pointers:
QLayoutItem *QGridLayout::itemAtPosition(int row, int column) const
QUndoStack *QUndoGroup::activeStack() const
QObject *QDropEvent::source() constwant more? :)
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const
is kinda like the GPL license - infectious and intentionally so :)
I won't bring the actual standardese page number, but a close-enough rule for this is on cppreference:If the operand is an lvalue expression of some object or function type T, operator& creates and returns a prvalue of type T*, with the same cv qualification, that is pointing to the object or function designated by the operand.
What this piece of the typical standardese mumbo jumbo translates to is that when you're doing
&member
inside a const method it's really&(this->member)
and cv-qualifiers (const and volatile) for the resulting pointer are taken from the objectthis
points to. Since you're inside a const methodthis
points to a const object in that scope and so&
returns a pointer to const member.Btw. I've seen an interesting debate somewhere (can't find it now, it was a while ago) about if
this
should be a const pointer to const object or just a pointer to const object i.e.T const *
vsT const * const
. The argument for non-constthis
pointer was some wizardry with modifyingthis
inside a member to avoid vtables. It landed onthis
being a non-const prvalue and thus non-assignable, but those are some deep trenches :)@Christian-Ehrlicher said in Return pointer-to-member in const method:
If you want some further discussion points, take a look at how the Qt api returns pointers:
I believe the last two are just straight pointer retrievals so not a big deal. The first one needs that branching logic I mentioned so it's basically against all I've said, but that's a design choice Qt takes. It is well known to take small performance hits here and there for the sake of ease of use and I think it's a fair compromise for all that it offers in return - consistency being a big one. Not a design I would make but hey, can't have it all the way I like :)
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@Christian-Ehrlicher , @Chris-Kawa
QLayoutItem *QGridLayout::itemAtPosition(int row, int column) const
Does the
QLayoutItem*
returned here point to a member variable of theQGridLayout
? If it does, then that's what I want to achieve. -
@JonB Not really. It's more like
QGridLayout
has a container ofQLayoutItem*
s, notQLayoutItem
s. The container is const and the pointers become const but they don't point to const things. The pointer itself is basically copied on return so there's no problem with returning a non-const pointer. It's a by value return and you can copy a const value to non-const object no problem. -
@Chris-Kawa said in Return pointer-to-member in const method:
The container is const and the pointers become const but they don't point to const things
:)
Yeah, so what you're really saying is: you need to cheat/go complex like them if you want to achieve this. No, I do get it. There isn't, and isn't supposed to be, a neat, simple way to do what I want (obtain this behaviour on a straightforward member).
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Heh, maybe C++ needs a permission system similar to *nix filesystems?
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