How to get the position of widgets in QTablewidget

[MasterBlade]

@Bonnie
I used ui->table->setCellWidget(j, 2, cb); to setup the widget.

After changing to QPoint p = w->mapTo(ui->table, pos);
it still crashed with exactly the same error message.

[EDIT]
I tried

QPoint global = w->mapToGlobal(pos);
QPoint p = ui->table->mapFromGlobal(global);

It didn't crash. But I'm having issues with QtCreator. It's not showing watchlist.
But I'm sure row is a negative value because the program went into

if (row < 0){
//
}

[Bonnie]

@MasterBlade Wait! I found that in your code the ContextMenu is not called as a slot.
So the sender() should not be the comboBox...

[MasterBlade]

@Bonnie It's a lambda function and should work.

Actually I also connected the table with this function.

connect(ui->table, &QTableWidget::customContextMenuRequested, [=](QPoint pos){ContextMenu(pos);});

This is working alright. I can get the correct row number.

[Bonnie]

@MasterBlade But that's not the correct way to use sender()

1. If EffectTable::ContextMenu is declared as a slot, use

connect(cb, &QComboBox::customContextMenuRequested, this, &EffectTable::ContextMenu);

2. If not , try this and don't do any mapping in EffectTable::ContextMenu, leave it same as in the top post

    connect(cb, &QComboBox::customContextMenuRequested, [=](QPoint pos){
        QWidget* w = qobject_cast<QWidget*>(sender());
        ContextMenu(w->mapTo(ui->table->viewport(), pos));
    });

[MasterBlade]

@Bonnie

You are correct. I output sender with

QObject* obj = sender();
qDebug() << obj;

and got

QObject(0x0)

sender is not working in this case.

[MasterBlade]

@Bonnie There is a compile error with ContextMenu(w->mapTo(ui->table->viewport(), pos));

C:\Users\<...>\effecttable.cpp:132: error: non-const lvalue reference to type 'QPoint' cannot bind to a temporary of type 'QPoint'

I changed it to

QPoint p = w->mapTo(ui->table->viewport(), pos);
ContextMenu(p);

and it's running.

But it again crashed with the same error message.

[MasterBlade]

@Bonnie said in How to get the position of widgets in QTablewidget:

connect(cb, &QComboBox::customContextMenuRequested, this, &EffectTable::ContextMenu);

connect(cb, &QComboBox::customContextMenuRequested, this, &EffectTable::ContextMenu);

has a link error.
C:\Qt\5.15.0\msvc2019_64\include\QtCore\qobject.h:255: error: C2338: Signal and slot arguments are not compatible.

[MasterBlade]

@Bonnie It's late at night in China and I need to take some sleep.
Thank you so much for the help.
I will answer your further responses tomorrow.

[Bonnie]

@MasterBlade I've tried myself. sender() is still 0x0.
Seems not a good idea to use it in the lambda. We should use cb instead.
Still in the lambda:

QPoint p = cb->mapTo(ui->table, pos);
ContextMenu(p);

And no mapping in ContextMenu.
I've tried, this works. ;)

[MasterBlade]

@Bonnie Oh god this is working!
Thank you so much!

[MasterBlade]

@Bonnie Well there are still some minor problems.

I have QComboBox and QPushbutton on the same row.

Let's say the first row. Right-clicking the QPushbutton gives row# 0, but QComboBox gives 1.

Also for the last row both give -1.

They are linked the the same ContextMenu() function.

[Bonnie]

@MasterBlade I've tried again, to get the correct row, we need to map to the viewport, as I expected.
So in the lambda

QPoint p = cb->mapTo(ui->table->viewport(), pos);
ContextMenu(p);

I also tried to add a QPushButton, it works fine, too.
How did you connect the button?
Did you change cb to the button's pointer?

[MasterBlade]

@Bonnie
After adding viewport everything works perfect!
I wish I could give you 100 thumbs up!!!