Widget's geometry before first show
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looks like no APIs to make such a call. what is your use case? why isn't QRect() enough?
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So, I has several widgets in QStackedLayout. All these widgets are hidden when programme starts. But on button click I want to start animation, in which corresponding widget's geometry() will be changed from button's geometry() to geometry of this widget, when it is shown (and at end of the animation call widget->show()). So, I must know its geometry before first show...
I think, it can be made by placing (and showing) empty dummy widget, before animation... -
You might not need dummy widgets. Have you seen the animation framework examples? You can play with QPropertyAnimation and animate the position, size, rotate and opacity properties and make the transitions look how you want.
And yes, you can add the widget itself to the layout and obtain the size before the show. the property animation can then take initial value from the button's size and end value will be the widget's size. You can also animate opacity from 0 to 1, so the widget will be hidden first and then fully appear at the end of the animation
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bq. You might not need dummy widgets. Have you seen the animation framework examples? You can play with QPropertyAnimation and animate the position, size, rotate and opacity properties and make the transitions look how you want.
Yes, of course, I know about QPropertyAnimation, and I use it.
But I apply it to painter (scale/translate) on which widget draws itself (by widget->render(&p)). I think that I can not apply QPropertyAnimation directly to my widget because it is quite complex and it will look ugly when it will have small sizes during animation. Furthermore, I want to get something looking like KDE animation, while minimizing windows.bq. And yes, you can add the widget itself to the layout and obtain the size before the show.
No, I can not... Yes, I can, but this size (before first show) is not correct - always equals to QRect(0, 0, 640x480)
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You mean, before show() if you use something like
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widget->setGeometry(QRect(30,30,200,200);
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it will still show QRect(0,0,640x480) ?can you check again and confirm?
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No, after this
@widget->setGeometry(QRect(30,30,200,200);@
geometry will become QRect(30,30,200,200)But where/how can I know proper values?
Furthermore,
"will still show QRect(0,0,640×480) or not after widget->setGeometry(X);" - is NOT the question.
Qustions is how to find correct X. -
can you upload your test file, can chk further
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Test code here
"http://pastebin.com/biVYTMvr":http://pastebin.com/biVYTMvrOutput is:
MainWindow::showEvent: Geometry of second button before show QRect(0,0 640x480)
MainWindow::on_Timer_timeout(): Geometry of second button after show QRect(0,0 200x100) -
Usually, layouts try to respect preferredSize() values, however I'm not used to QStackLayout.
I'm remember when I was working with GraphicsLayout that there is no way to know the internal elements sizes before layout's "invalidade":http://doc.trolltech.com/4.6/qgraphicslayout.html#invalidate and "activate":http://doc.trolltech.com/4.6/qgraphicslayout.html#activate
The elements still needs to be rearranged.
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As soon as you create the widget, why not use
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Stack->widget(1)->setFixedSize(200,100);
@or to any other custom size?
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bq. or to any other custom size?
What is the custom size?
I do not know PROPER (correct) size. PROPER size = size of widget, when it fits its parent widget (Stack in the example)Of course, I can calculate (how it does Qt layout system) it by myself, but then I must write half of Qt layout system), to take into account indents, different platforms and so on...
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you are right, calculating the sizes though possible will be a tall order. In your case, you want to animate only on click of a button, at which points I assume all the widgets will be created, laid out in the layout, so will be sized properly.
That corresponds to the following in your test code ...
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void MainWindow::on_Timer_timeout()
{
qDebug() << "MainWindow::on_Timer_timeout(): Geometry of second button before animation" << Stack->currentWidget()->geometry();// At this point all widgets are laid out and sized properly, but the widget is still not shown // You can set the initial size and target size. Stack->setCurrentIndex(1); // widget is shown now with initial size... and you can animate at this point? qDebug() << "MainWindow::on_Timer_timeout(): Geometry of second button after show" << Stack->currentWidget()->geometry();}
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bq. you want to animate only on click of a button,
Yes
bq. at which points I assume all the widgets will be created,
Yes
bq. laid out in the layout,
Yes
bq. so will be sized properly.
No... They all added to QStackedLayout, but not shown. Only one (first of them) shown when app has started. And only after they all are shown though one time, they will have proper size. But at start, only on of them is shown...
Since they all has the same size, I think, I can use proper size of this first shown widget.
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QStackedWidget provides a stack of widgets where only one widget is visible at a time.
So i think the geometry of all widget if is not specific, it will be the geometry of the QStackedWidget.size of
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QStackedWidget->widget(0)->geometry();
QStackedWidget->widget(1)->geometry(); @after use
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QStackedWidget->setCurrentIndex(number);@is
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QStackedWidget->geometry();@But i not understand if this is useful for you or not :)
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[quote author="DimanNe" date="1287502693"]
almost equal - differs 2-3pixels.[/quote]i think they have to be equal, unless there a margin set?
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Did you try after creating widget call QWidget::adjustSize()? as recommended here:
http://stackoverflow.com/questions/4963220/qt-how-to-preview-sizes-of-widgets-in-layout-before-a-show -
You're right, I saw that ))), but as I understood DimanNe did find good solution. I've come across the same problem and QWidget::adjustSize() works well and looks better as for me. I posted that just for the case if someone like me has the same problem and check QWidget::adjustSize().