The model inherited from QAbstractTableModel throws errors

[Christian Ehrlicher]

@Mikeeeeee said in The model inherited from QAbstractTableModel throws errors:

What is the bug and how to fix it?

Christian Ehrlicher 18 minutes ago

And you should only return values for Qt::DisplayRole

[Mikeeeeee]

I fixed the code, there is no more error. But the column index is always zero. I don't understand how to fix this. Debag returns:
0 0
0 0
0 0
Model size of -3 is less than 0
0 1
0 1
0 1
0 2
0 2
0 2

[Mikeeeeee]

[Christian Ehrlicher]

@Mikeeeeee said in The model inherited from QAbstractTableModel throws errors:

I fixed the code

Please update your code in your example so we can see what you're doing.

[Mikeeeeee]

This post is deleted!

[Mikeeeeee]

@Christian-Ehrlicher I updated the code an hour ago. I didn't add anything after that.

[Mikeeeeee]

Maybe the problem is in QML?

import QtQuick 2.13
import QtQuick.Controls 1.4

Item {
    width: 380
    height: 680

    TableView {
        anchors.fill: parent
        TableViewColumn {
            role: "role1"
            title: "Column1"
            width: 100
        }
        TableViewColumn {
            role: "role2"
            title: "Column2"
            width: 100
        }
        TableViewColumn {
            role: "role3"
            title: "Column3"
            width: 100
        }
        model: myModel
    }

}

[Christian Ehrlicher]

Then you still did not read my comment about the Qt::DisplayRole. So stay on your own.

[Mikeeeeee]

I don't understand what you mean. Please answer in more detail and clearly.

[Mikeeeeee]

Its work

QVariant MyModel::data(const QModelIndex & index, int role) const {
    if (index.row() < 0 || index.row() >= list1.count())
        return QVariant();
    if(role == 0){
        return QVariant(list1[index.row()]);
    }
    if(role == 1){
        return QVariant(list2[index.row()]);
    }
    if(role == 2){
        return QVariant(list3[index.row()]);
    }
    return QVariant();
}