General question about arrays and I/o
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@Please_Help_me_D said in General question about arrays and I/o:
So is there a way to extract few elements from an array at the same time without loop?
Not with plain C arrays.
But you can do this with QVector: https://doc.qt.io/qt-5/qvector.html#mid
There is something you can do without copying anything: an array is just a pointer to first element, so:int data[5] = {1, 2, 3, 4, 5}; int *data2 = &data[2]; // data2 is now [3, 4, 5].Do you really need to copy to data2? You can simply have a variable "length" containing the length of the sub-array in data.
"My compiler is MSVC 2017. Could you write an example of this?":
char *char_file = new char[n]; // Allocate on the heap ... delete[] char_file; // Delete when not needed anymore@jsulm thank you for the answer
The problem is that usually I have I know indexes are maybe like:int data[4] = {1, 2, 3, 4, 5}; int ind[3] = {4, 2, 3};and then I need to get access to those elements like:
int data2[3] = data[ind];Now I read about QVector, I hope it is able to do that.
You know both examples that you wrote seems to me don't work properly.
int data[5] = {1, 2, 3, 4, 5}; int *data2 = &data[2]; // data2 is now [3].And:
int n = 5; char char_file = new char[n]; // error: cannot initialize a variable of type 'char' with an rvalue of type 'char *' delete[] char_file; // Delete when not needed anymoreWhere can I read about '*' and '&' signs when using in such ways? What it gives?
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@jsulm thank you for the answer
The problem is that usually I have I know indexes are maybe like:int data[4] = {1, 2, 3, 4, 5}; int ind[3] = {4, 2, 3};and then I need to get access to those elements like:
int data2[3] = data[ind];Now I read about QVector, I hope it is able to do that.
You know both examples that you wrote seems to me don't work properly.
int data[5] = {1, 2, 3, 4, 5}; int *data2 = &data[2]; // data2 is now [3].And:
int n = 5; char char_file = new char[n]; // error: cannot initialize a variable of type 'char' with an rvalue of type 'char *' delete[] char_file; // Delete when not needed anymoreWhere can I read about '*' and '&' signs when using in such ways? What it gives?
@Please_Help_me_D said in General question about arrays and I/o:
seems to me don't work properly
In what way? &data[2] points to 3 in data, so data2[0] == 3, data2[1] == 4 and data2[2] == 5
Please read about pointers in C/C++:
// It must be *char_file not just char_file char *char_file = new char[n];I edited my previous post as I forgot *
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@Please_Help_me_D said in General question about arrays and I/o:
seems to me don't work properly
In what way? &data[2] points to 3 in data, so data2[0] == 3, data2[1] == 4 and data2[2] == 5
Please read about pointers in C/C++:
// It must be *char_file not just char_file char *char_file = new char[n];I edited my previous post as I forgot *
In what way? &data[2] points to 3 in data, so data2[0] == 3, data2[1] == 4 and data2[2] == 5
I attach the picture below. data2 is now is equal to 3 and that is it. Is it correct?
After I added * pointer the program works but seems to me that the length of char_file doesn't depend on n. If n=4 then length of char_file=32, n=5 then char_file=32. Is it ok?
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In what way? &data[2] points to 3 in data, so data2[0] == 3, data2[1] == 4 and data2[2] == 5
I attach the picture below. data2 is now is equal to 3 and that is it. Is it correct?
After I added * pointer the program works but seems to me that the length of char_file doesn't depend on n. If n=4 then length of char_file=32, n=5 then char_file=32. Is it ok?
@Please_Help_me_D said in General question about arrays and I/o:
data2 is now is equal to 3 and that is it. Is it correct?
Yes it is, you can treat a pointer as an array (actually in C/C++ an array is simply a pointer to first element of the array). So, data2[0] == 3, data[1] == 4...
Just doqDebug() << data2[1];and see.
Regarding second question: this is debugger view. Your array is for sure 4 char in size. To verify do
char_file[4] = 1;your app should crash.
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@Please_Help_me_D said in General question about arrays and I/o:
data2 is now is equal to 3 and that is it. Is it correct?
Yes it is, you can treat a pointer as an array (actually in C/C++ an array is simply a pointer to first element of the array). So, data2[0] == 3, data[1] == 4...
Just doqDebug() << data2[1];and see.
Regarding second question: this is debugger view. Your array is for sure 4 char in size. To verify do
char_file[4] = 1;your app should crash.
@jsulm Yes that works:
int data[5] = {1, 2, 3, 4, 5}; int *data2 = &data[2]; // data2 is now [3, 4, 5]. qDebug() << data2[2];But what's the magic behind that?:) I debug I can see that data2 has only a single number.
But this doesn't crash and I can see some output in terminal (it is not 100 but some letters or signs as I think it is char) even if I lauch the program not in debug mode:
int n = 2; char *char_file = new char[n]; // error: cannot initialize a variable of type 'char' with an rvalue of type 'char *' delete[] char_file; // Delete when not needed anymore char_file[5] = 100; std::cout << char_file[5];Are there in Qt the possibility to use command line when the program stopped in debug mode? For example if it's stopped and I want to do something in real time (while the program is topped)? Like in Matlab command line in debug mode
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@jsulm Yes that works:
int data[5] = {1, 2, 3, 4, 5}; int *data2 = &data[2]; // data2 is now [3, 4, 5]. qDebug() << data2[2];But what's the magic behind that?:) I debug I can see that data2 has only a single number.
But this doesn't crash and I can see some output in terminal (it is not 100 but some letters or signs as I think it is char) even if I lauch the program not in debug mode:
int n = 2; char *char_file = new char[n]; // error: cannot initialize a variable of type 'char' with an rvalue of type 'char *' delete[] char_file; // Delete when not needed anymore char_file[5] = 100; std::cout << char_file[5];Are there in Qt the possibility to use command line when the program stopped in debug mode? For example if it's stopped and I want to do something in real time (while the program is topped)? Like in Matlab command line in debug mode
@Please_Help_me_D said in General question about arrays and I/o:
Are there in Qt the possibility to use command line when the program stopped in debug mode? For example if it's stopped and I want to do something in real time (while the program is topped)? Like in Matlab command line in debug mode
No, this is a C++ compiled program (nothing to do with Qt), not Matlab/an interpreted language! You can print out values, and even at a pinch poke a value into a variable, but you can't start "telling" the debugger/program to go perform actions :)
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@jsulm Yes that works:
int data[5] = {1, 2, 3, 4, 5}; int *data2 = &data[2]; // data2 is now [3, 4, 5]. qDebug() << data2[2];But what's the magic behind that?:) I debug I can see that data2 has only a single number.
But this doesn't crash and I can see some output in terminal (it is not 100 but some letters or signs as I think it is char) even if I lauch the program not in debug mode:
int n = 2; char *char_file = new char[n]; // error: cannot initialize a variable of type 'char' with an rvalue of type 'char *' delete[] char_file; // Delete when not needed anymore char_file[5] = 100; std::cout << char_file[5];Are there in Qt the possibility to use command line when the program stopped in debug mode? For example if it's stopped and I want to do something in real time (while the program is topped)? Like in Matlab command line in debug mode
@Please_Help_me_D said in General question about arrays and I/o:
But what's the magic behind that?:) I debug I can see that data2 has only a single number.
Pointer magic :-) data2 is defined as pointer to int, that's why debugger only shows one value. But you as developer know that it's actually pointing to an array of int. Writing data2[1] is same as *(data2 + 1).
*(data2 + 1) means: give me the value in memory at the position (data2 + 1) is pointing to.
Keep in mind that in this case (data2 + 1) increments the pointer by 4 as sizeof(int) == 4.This should actually crash as you're accessing memory which was already freed:
delete[] char_file; // Delete when not needed anymore char_file[5] = 100; std::cout << char_file[5]; -
@Please_Help_me_D said in General question about arrays and I/o:
Are there in Qt the possibility to use command line when the program stopped in debug mode? For example if it's stopped and I want to do something in real time (while the program is topped)? Like in Matlab command line in debug mode
No, this is a C++ compiled program (nothing to do with Qt), not Matlab/an interpreted language! You can print out values, and even at a pinch poke a value into a variable, but you can't start "telling" the debugger/program to go perform actions :)
@JonB thank you! Now I know that:)
@jsulm ok that is interesting. I need to read about pointers
I read about QVector and I can't solve the situation when I need to extract {4, 2, 3} elements from data (without loop) so that:
data2[0] = data[4] = 5,
data2[1] = data[2] = 3,
data2[2] = data[3] = 4 ,
where data = {1, 2, 3, 4, 5};
Seems to me that QVector::mid(int pos, int length = ...) can't do that. But of coarse:QVector<int> data = {1, 2, 3, 4, 5}; QVector<int> data2 = data.mid(1,2); // data2 = {2, 3}this is also good to know for me.
I'm trying to avoid loops here because it is like the main standart operation for me and I feel there should be a way to do that. -
@JonB thank you! Now I know that:)
@jsulm ok that is interesting. I need to read about pointers
I read about QVector and I can't solve the situation when I need to extract {4, 2, 3} elements from data (without loop) so that:
data2[0] = data[4] = 5,
data2[1] = data[2] = 3,
data2[2] = data[3] = 4 ,
where data = {1, 2, 3, 4, 5};
Seems to me that QVector::mid(int pos, int length = ...) can't do that. But of coarse:QVector<int> data = {1, 2, 3, 4, 5}; QVector<int> data2 = data.mid(1,2); // data2 = {2, 3}this is also good to know for me.
I'm trying to avoid loops here because it is like the main standart operation for me and I feel there should be a way to do that.@Please_Help_me_D
I will say one thing about "loops": although you may try to avoid, it is likely that even if there is a library call that will do a loop. (Not always true, some adjacent elements may be implemented by amemmoveor similar.) Even your Matlab or whatever may present an an operation as "non-loop" as far as you are concerned, but under the hood that is what it will have to do. C++ is "lower-level" and more "literal" about what is going on/has to go on than a higher level language like Matlab may suggest to you. Not saying you shouldn't ask, or try to avoid, but be aware it may be inevitable.In your example, btw, technically there is no loop. It's just what it looks like: 3 separate statements (which cannot be optimized for non-adjacent data). And someone here will tell you these will take about 3 nanoseconds to perform.
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@Please_Help_me_D
I will say one thing about "loops": although you may try to avoid, it is likely that even if there is a library call that will do a loop. (Not always true, some adjacent elements may be implemented by amemmoveor similar.) Even your Matlab or whatever may present an an operation as "non-loop" as far as you are concerned, but under the hood that is what it will have to do. C++ is "lower-level" and more "literal" about what is going on/has to go on than a higher level language like Matlab may suggest to you. Not saying you shouldn't ask, or try to avoid, but be aware it may be inevitable.In your example, btw, technically there is no loop. It's just what it looks like: 3 separate statements (which cannot be optimized for non-adjacent data). And someone here will tell you these will take about 3 nanoseconds to perform.
@JonB Yes I understand that many function that don't use explicitly loops they use them under the hood. But I believe that in computer science there are some tricks that I don't know and that provide high perfomance of operations and specialists who write Qt functions (or Matlab functions) they implement those tricks to achieve good optimization of code.
I'm just starting learning Qt I think I just need experience in C++ :) -
@JonB thank you! Now I know that:)
@jsulm ok that is interesting. I need to read about pointers
I read about QVector and I can't solve the situation when I need to extract {4, 2, 3} elements from data (without loop) so that:
data2[0] = data[4] = 5,
data2[1] = data[2] = 3,
data2[2] = data[3] = 4 ,
where data = {1, 2, 3, 4, 5};
Seems to me that QVector::mid(int pos, int length = ...) can't do that. But of coarse:QVector<int> data = {1, 2, 3, 4, 5}; QVector<int> data2 = data.mid(1,2); // data2 = {2, 3}this is also good to know for me.
I'm trying to avoid loops here because it is like the main standart operation for me and I feel there should be a way to do that.@Please_Help_me_D said in General question about arrays and I/o:
I need to extract {4, 2, 3}
You will need to do it by yourself. There is nothing for that neither in Qt nor in C++ stdlib. Even if there would be it would do nothing else as iterating over {4, 2, 3} in a loop. So, I doubt you can optimise here much.
