load two file qml

[vale88]

I wrote:

      ui->quickWidget->setSource(QUrl("qrc:///qml.qml"));

 ui->quickWidget_2->setSource(QUrl("qrc:///sl.qml"));

but the second isn't loaded..

my sl.qml is:

import QtQuick 2.0
import QtQuick.Extras 1.4
import QtGraphicalEffects 1.0
import QtQuick.Window 2.10

Item {
    Dial {
        id: dial
        x: 197
        y: 94
    }

}

my project:

[Pradeep P N]

Hi @vale88

Can you please provide width & height for your Item { }.
You can even directly use Dial {} without Item {}.

Sample code :

• CPP

Widget::Widget(QWidget *parent)
    : QWidget(parent)
    , _HBLyt(new QHBoxLayout(this))
    , _qml1(new QQuickWidget)
    , _qml2(new QQuickWidget)
{

    _qml1->setSource(QUrl::fromLocalFile(":/One.qml"));
    _qml2->setSource(QUrl::fromLocalFile(":/Two.qml"));

    _HBLyt->addWidget(_qml1);
    _HBLyt->addWidget(_qml2);

}

• QML
  • One.qml & Two.qml

import QtQuick 2.9
import QtQuick.Extras 1.4

Item {
    width: 100;
    height: 100

    Dial { }
}
--------------------------
import QtQuick 2.9

Rectangle {
    width: 100;
    height: 100
    color: 'red'
}

Result of my sample:

All the best

[vale88]

This post is deleted!

[vale88]

@Pradeep-P-N it's strange because in qml I have this image:

in mainwindow this:

[Pradeep P N]

@vale88
Can you please share me your Dial {} sample code if possible ?

Below is the result of using Customizing Dial.

[vale88]

@Pradeep-P-N

import QtQuick 2.0
import QtQuick.Extras 1.4
import QtGraphicalEffects 1.0
import QtQuick.Window 2.10
import QtQuick.Controls 2.3


Item{
    x: 10
    y: 0

    width:100
    height:100


Dial{
id: control

from:0
to:100


    background: Rectangle {
        x: 5
        y: 5
        width: 70
        height:70
        color: "black"
        radius: width / 2
        transformOrigin: Item.Right
        border.color: control.pressed ? "#17a81a" : "#21be2b"
        opacity: control.enabled ? 1 : 0.3

    }

//    handle: Rectangle {
//        id: handleItem
//        x: control.background.x + control.background.width / 2 - width / 2
//        y: control.background.y + control.background.height / 2 - height / 2
//        width: 12
//        height: 12
//        color: "white"
//        radius: 8
//        antialiasing: true
//        opacity: control.enabled ? 1 : 0.3
//        transform: [
//            Translate {
//                y: -Math.min(control.background.width, control.background.height) * 0.4 + handleItem.height / 2
//            },
//            Rotation {
//                angle: control.angle
//                origin.x: handleItem.width / 2
//                origin.y: handleItem.height / 2
//            }
//        ]
//    }

Connections
{
    target: yourObject1
    onSliderMoved: control.value = (position)
}



}
}

I have also problem with connection..in mainwindow.cpp I wrote:

    ui->quickWidget->engine()->rootContext()->setContextProperty("yourObject",ui->horizontalSlider);

    ui->quickWidget_2->engine()->rootContext()->setContextProperty("yourObject1",ui->horizontalSlider_3);






    ui->quickWidget->setSource(QUrl("qrc:///qml.qml"));

    ui->quickWidget_2->setSource(QUrl("qrc:///sl.qml"));

[Pradeep P N]

@vale88
It looks fine for me,

I have just used your code. and just removed the Connection {} to Slider

All the best.

[vale88]

@Pradeep-P-N

I don't understand, I have problems when I show my qml dial in mainwindow

[Pradeep P N]

@vale88

• Which platform and Qt you are using. I am working with Qt 5.9.8 on Windows
• Do you have any warnings or errors in your Application Output ?

Below is with Connections {} - QSlider

All the best.

[vale88]

@Pradeep-P-N qt creator with MSCV compiler,

I saw that if I use two different projects it works, but I have two files qml with connection and it doesn't work
can I send you my project?

[Pradeep P N]

@vale88

[vale88]

@Pradeep-P-N uff...for me it isn't..maybe is it compiler?
can you send me code modified? also do connections work?

[Pradeep P N]

@vale88 sure. I can.
Are you sure you don't have qml errors warnings. ?

[vale88]

@Pradeep-P-N yes I have a warning: