Qt signal-slot duplication code avoidance

[KillerSmath]

@vernes
QObject don't support multiple inheritances because of MOC. I suggest you to think in a hasA relationship instead of isA.

Virtual inheritance with QObject is not supported.

[arsinte_andrei]

@vernes why on earth will you have 2 different classes that are emitting the very same name signall for the very same thing? and to process the very same data at the very same time and both of them to be the inherited classes for the 3rd which is doing the very same thing?? it just doesn't make any sense at all - I've already explained to you how qsocket work.. and is processing signals from different classes that it inherited from I do not see where the confusion can be? I mean the signal slot connector in Qt is very mature and is doing a great job... there is no confusion even for the compiler this is why we have moc files - to avoid confusions...
so your problem doesn't make any sense at least to me... I've done many classes that extend 2 or 3 classes without any problems in managing the signals from them - maybe had to reimplement some of the signals.. but that's the way it is.. you can have a look at Qt source... many times a class is not doing anything except putting together 2 classes

[vernes]

@KillerSmath said in Qt signal-slot duplication code avoidance:

Virtual inheritance with QObject i

Ok, I suspected that. I'm just trying to find the best solution to not repeat code.

Basically, in my design, B is a class that contains different classes A, C, D, E, all of them that have different signals.
B must just forward signals, My idea was to create signals in helper classes. E.g. ASignals, CSignals, DSignals, ESignals,
and do something like A : public ASignals, C : public CSignals etc. B should then extend only one QObject and all the
signals classes B: public QObject, ASignals, CSignals, DSignals, ESignals. Ideally I would like to do this same trick for slots.

Is there a way to circumvent this virtual inheritance problem in this way?

[vernes]

@arsinte_andrei said in Qt signal-slot duplication code avoidance:

@vernes why on earth will you have 2 different classes that are emitting the very same name signall for the very same thing? and to process the very same data at the very same time and both of them to be the inherited classes for the 3rd which is doing the very same thing?? it just doesn't make any sense at all - I've already explained to you how qsocket work.. and is processing signals from different classes that it inherited from I do not see where the confusion can be? I mean the signal slot connector in Qt is very mature and is doing a great job... there is no confusion even for the compiler this is why we have moc files - to avoid confusions...
so your problem doesn't make any sense at least to me... I've done many classes that extend 2 or 3 classes without any problems in managing the signals from them - maybe had to reimplement some of the signals.. but that's the way it is.. you can have a look at Qt source... many times a class is not doing anything except putting together 2 classes

It doesn't make sense if you don't know the context. I'm trying to managing complexity, using different QThreads. The class that is B is a class that has to manage all the signals coming from the threads, do some stuff, and re-emitting these signals. Why this? because of maintainability / modularity, that's now too long to explain.

[KillerSmath]

@vernes

You can implement a hasX (composition) relationship

class A : public QObject // is QObject
{
    Q_OBJECT
public:
    A() {}
signals:
    void mySignal();
};

class B : public QObject // is QObject
{
    Q_OBJECT
public:
    B(){}

signals:
    void mySignal();
};

class C : public QObject // is QObject
{
    Q_OBJECT

public:
    C()
    {
        connect(this, &C::sendToA, &a, &A::mySignal);
        connect(this, &C::sendToB, &b, &B::mySignal);

        connect(&a, &A::mySignal, [](){qDebug() << "A signal emitted";});
        connect(&b, &B::mySignal, [](){qDebug() << "B signal emitted";});
    }

signals:
    void sendToA();
    void sendToB();
private:
    A a; // has A
    B b; // has B
};

[vernes]

@KillerSmath said in Qt signal-slot duplication code avoidance:

@vernes

You can implement a hasX (composition) relationship

class A : public QObject // is QObject
{
    Q_OBJECT
public:
    A() {}
signals:
    void mySignal();
};

class B : public QObject // is QObject
{
    Q_OBJECT
public:
    B(){}

signals:
    void mySignal();
};

class C : public QObject // is QObject
{
    Q_OBJECT

public:
    C()
    {
        connect(this, &C::sendToA, &a, &A::mySignal);
        connect(this, &C::sendToB, &b, &B::mySignal);

        connect(&a, &A::mySignal, [](){qDebug() << "A signal emitted";});
        connect(&b, &B::mySignal, [](){qDebug() << "B signal emitted";});
    }

signals:
    void sendToA();
    void sendToB();
private:
    A a; // has A
    B b; // has B
};

Thank you for the feedback. It's my current approach, but as I said I'm trying to remove duplicated code :)

[CP71]

@vernes
Maybe I lost something! Or I don't understand your issue!
You don’t need of inherit from multiple classes.

If I have to do something like this I would do:

class CommonSignals : public QObject
{
Q_OBJECT
public:
CommonSignals( QObject *parent = NULL);

signals:
void mysignal();

};

class A : public CommonSignals
{
Q_OBJECT
public:
A( QObject *parent = NULL )

void doSomething()
{
	emit mysignal();
}

};

class B : public CommonSignals
{
Q_OBJECT

public:

B(QObject *parent = NULL ) : CommonSignals(parent)
{
  connect(&a, &A::mysignal, this, &B::mysignal);
}

A a;

};

Maybe I read too fast and don’t understand your issue or your code.
Sorry

[vernes]

@CP71 said in Qt signal-slot duplication code avoidance:

CommonSignals

Thank you for your feedback. The goal is to make B use CommonSignals1, CommonSignals2, CommonSignals3 together in the same class

Code example:

class CommonSignalsA : public QObject
{
Q_OBJECT
public:
CommonSignalsA( QObject *parent = NULL);

signals:
void mysignal();
};

class CommonSignalsB : public QObject
{
Q_OBJECT
public:
CommonSignalsB( QObject *parent = NULL);

signals:
void mysignal2();
};

class A : public CommonSignalsA
{
Q_OBJECT
public:
A( QObject *parent = NULL )

void doSomething()
{
	emit mysignal();
}
};

class B : public CommonSignalsB
{
Q_OBJECT
public:
B( QObject *parent = NULL )

void doSomething2()
{
	emit mysignal2();
}
};

class C : public CommonSignalsA,  public CommonSignalsB
{
Q_OBJECT

public:

C(QObject *parent = NULL ) : CommonSignalsA(parent), CommonSignalsB(parent)
{
  connect(&a, &A::mysignal, this, &C::mysignal);
connect(&b, &B::mysignal2, this, &C::mysignal2);
}

A a;
B b;
};

Basically, my question is: is it possible to create a CommonSignals that doesn't use QObject, or however making this work with same trick.. maybe passing QObject in same way.

[KillerSmath]

@vernes
One point i would like to talk about here.
The Software engineering warns to use the minimum coupling while maximize the cohesion of class.

Note: Inheritance is a 2 edged weapon, reusability is good but dependence is bad.

If you decide to modify a class with a high dependency level, it can break the logic of some dependent class and it can be recursive.

[vernes]

@KillerSmath said in Qt signal-slot duplication code avoidance:

@vernes
One point i would like to talk about here.
The Software engineering warns to use the minimum coupling while maximize the cohesion of class.

Note: Inheritance is a 2 edged weapon, reusability is good but dependence is bad.

If you decide to modify a class with a high dependency level, it can break the logic of some dependent class and it can be recursive.

Good point here. However I would say that the approach I'm describing is much better compared to a lot of copy & paste.

I'd avoid use inheritance but unfortunately Qt seems encouraging it.

Problem is Qt and templates do not work well together, and many things like CRTP are not possible in many cases.