Number Type Cast

[koahnig]

@JonB

OK, I should have the "IIRC" there as I had before. Apparently current versions of MinGW do not.

Anyway, I tend to get rid of warnings as much as possible. Mainly because I left warnings in the far past and a missed warning caught me later on.

[kshegunov]

@J.Hilk said in Number Type Cast:

actually no,

Actually yes. Almost all errors that fall in the -fpermissive are there to prevent you from shooting yourself in the foot. The compiler can compile it just fine, hence the existence of the aforementioned flag. As a matter of fact if you try it with MSVC you're (probably with surprise) going to realize that it eats it just fine - no errors, just a warning or so.

as int my be a smaller type than a pointer ;-)

So? Substitute void * with long long and see what happens ... pure magic ... Truncation is unimportant here, and truncation is not an error by the way.

Don't we have const_cast for the above mentioned cases ?

Indeed, and some compilers may just allow you to static_cast it too depending on the types and how the compiler's implemented. However, here's a better snippet for your consideration:

typedef void* voidp;

const int * x;
void * y = static_cast<voidp>(x); // Case 1
void * z = voidp(x);              // Case 2

Case 1 is an error, because you're trying to const_cast and static_cast at the same time, Case 2 is valid and compiles fine. Most of the time this is harmless, obviously, as with the case of primitive types, but, and I repeat again, there's no semantic difference between C-style casts and constructor-style casts; they are exactly the same thing.

[Kent-Dorfman]

As I often need to code in several different languages I try to make my expressions as language agnostic as possible. Unless performance is a consideration I often do this to force a type conversion:

int a(12);
int b(15);
double d(a / (b + 0.0));

in many lanuages there will be an implicit conversion to floating point, and I prefer my conversion in the denominator.

[JonB]

@Kent-Dorfman This is a new one on me --- try to write code in one language so it will also work in another :)

[fcarney]

I have nothing significant to add to this discussion other than I still do C style casts in my C++ code. I am still not used to using all the new casting templates (they are templates right?).

So whether you use C or C++ casts just Cast Away!

[kshegunov]

@fcarney said in Number Type Cast:

they are templates right?

No, they're operators.

[beecksche]

Really interesting disucssion. I'm with @jsulm and use the "constructor-style cast" for primitives types.

int a = 10;
double b = double(a);

And for safety reasons *_cast for classes

MyBaseClass *base;

MyDerivedClass *derived = static_cast<MyDerivedClass*>(base);

[jsulm]

@beecksche I actually wrote that C style casts should be avoided in general (means: for all types including primitive types).

[SGaist]

@beecksche said in Number Type Cast:

MyDerivedClass derived = static_cast<MyDerivedClass>(base);

Just one note: static_cast has absolutely no notion of safety. There's no check involved so you are completely responsible to ensure that the type you are casting to is really is valid with regard to the type you are casting from.

dynamic_cast does check and in the case of pointers return a null pointer that you can validate before continuing your code.

[beecksche]

@jsulm , @SGaist

thanks a lot. I thought I had understood the problem. But it seems to be a bit more complicated.

Hopefully, in some time, I will understande when to use which cast explicitly and for what reason.

Until thenI hope that these parts of the code don't make any trouble.