Skip to content
  • Categories
  • Recent
  • Tags
  • Popular
  • Users
  • Groups
  • Search
  • Get Qt Extensions
  • Unsolved
Collapse
Brand Logo
  1. Home
  2. Special Interest Groups
  3. C++ Gurus
  4. C++ % " ?
Forum Updated to NodeBB v4.3 + New Features

C++ % " ?

Scheduled Pinned Locked Moved Solved C++ Gurus
26 Posts 9 Posters 10.0k Views 6 Watching
  • Oldest to Newest
  • Newest to Oldest
  • Most Votes
Reply
  • Reply as topic
Log in to reply
This topic has been deleted. Only users with topic management privileges can see it.
  • J.HilkJ J.Hilk

    @JonB said in C++ % " ?:

    @Konstantin-Tokarev
    LOL! Wait!! You can overload the C comma operator? OMG!

    There is hardly a thing one can't change/overload in c++.
    But you do, the operation should be somewhat related to the original. Otherwise you'll end up with confusion and lost development time.

    I'm looking at you boost 0_1537780536073_34207ed0-bfd8-4865-9798-02d5853acddc-image.png

    JonBJ Online
    JonBJ Online
    JonB
    wrote on last edited by
    #11

    @J.Hilk
    LOL, I don't know about Boost. But how's about the subject of this post: how is this QString % operator related to original modulus?

    K J.HilkJ 2 Replies Last reply
    0
    • K Offline
      K Offline
      koahnig
      wrote on last edited by
      #12

      Hope you cannot overload ';' That would probably cause the ultimate confusion.

      Vote the answer(s) that helped you to solve your issue(s)

      JonBJ 1 Reply Last reply
      2
      • K koahnig

        Hope you cannot overload ';' That would probably cause the ultimate confusion.

        JonBJ Online
        JonBJ Online
        JonB
        wrote on last edited by JonB
        #13

        @koahnig ; is not an operator. I believe it is a "statement separator" (whereas Pascal had it as a "statement terminator"... or is it the other way round?).

        K 1 Reply Last reply
        3
        • JonBJ JonB

          @koahnig ; is not an operator. I believe it is a "statement separator" (whereas Pascal had it as a "statement terminator"... or is it the other way round?).

          K Offline
          K Offline
          koahnig
          wrote on last edited by
          #14

          @JonB

          Thanks for clarification, I am so happy about that ;)

          However, with the ancient FORTRAN they discussed a COME FROM statement
          Therefore, you never know what somebody will come up with. At least FORTRAN did not require a "statement separator" nor a "statement terminator". The logical end of aline was the end of the punching card after 80 chars respectively you had to subtract 8 digits for the line number.

          Vote the answer(s) that helped you to solve your issue(s)

          1 Reply Last reply
          1
          • JonBJ JonB

            @J.Hilk
            LOL, I don't know about Boost. But how's about the subject of this post: how is this QString % operator related to original modulus?

            K Offline
            K Offline
            Konstantin Tokarev
            wrote on last edited by
            #15

            @JonB said in C++ % " ?:

            @J.Hilk
            LOL, I don't know about Boost. But how's about the subject of this post: how is this QString % operator related to original modulus?

            modulus has no established meaning for strings, and % looks somewhat similar to + :)

            1 Reply Last reply
            3
            • K Offline
              K Offline
              Konstantin Tokarev
              wrote on last edited by
              #16

              Though you should better define QT_USE_QSTRINGBUILDER and simply use + everywhere instead of %

              JonBJ 1 Reply Last reply
              4
              • K Konstantin Tokarev

                Though you should better define QT_USE_QSTRINGBUILDER and simply use + everywhere instead of %

                JonBJ Online
                JonBJ Online
                JonB
                wrote on last edited by
                #17

                @Konstantin-Tokarev said in C++ % " ?:

                Though you should better define QT_USE_QSTRINGBUILDER and simply use + everywhere instead of %

                Ooohhh, the plot thickens...!

                1 Reply Last reply
                0
                • JonBJ JonB

                  @J.Hilk
                  LOL, I don't know about Boost. But how's about the subject of this post: how is this QString % operator related to original modulus?

                  J.HilkJ Online
                  J.HilkJ Online
                  J.Hilk
                  Moderators
                  wrote on last edited by
                  #18

                  @JonB Qt has ome confusing operaters as well.

                  for example take QVectors +=

                  QVector<T> QVector::operator+(const QVector<T> &other) const
                  

                  I would asume this to be Vector addtion

                  QVector v1{a,b,c};
                  QVector v2{d,e,f};
                  
                  //What one would expect
                  v1 += v2; -> {a+d, b+e, c+f}
                  
                  //what one gets
                  v1 +=v2; _> {a,b,c,d,e,f}
                  

                  I mean, this technically makes sense. QVector is to generic to have this operation, thats why there is QVector2D, 3D, 4D etc

                  It still confused me the first time I used it. I did not expect += to be equal to .append() or <<;

                  In this paticular example I have would prefere a missing += operator :-).


                  Be aware of the Qt Code of Conduct, when posting : https://forum.qt.io/topic/113070/qt-code-of-conduct


                  Q: What's that?
                  A: It's blue light.
                  Q: What does it do?
                  A: It turns blue.

                  jsulmJ JKSHJ 2 Replies Last reply
                  0
                  • J.HilkJ J.Hilk

                    @JonB Qt has ome confusing operaters as well.

                    for example take QVectors +=

                    QVector<T> QVector::operator+(const QVector<T> &other) const
                    

                    I would asume this to be Vector addtion

                    QVector v1{a,b,c};
                    QVector v2{d,e,f};
                    
                    //What one would expect
                    v1 += v2; -> {a+d, b+e, c+f}
                    
                    //what one gets
                    v1 +=v2; _> {a,b,c,d,e,f}
                    

                    I mean, this technically makes sense. QVector is to generic to have this operation, thats why there is QVector2D, 3D, 4D etc

                    It still confused me the first time I used it. I did not expect += to be equal to .append() or <<;

                    In this paticular example I have would prefere a missing += operator :-).

                    jsulmJ Offline
                    jsulmJ Offline
                    jsulm
                    Lifetime Qt Champion
                    wrote on last edited by
                    #19

                    @J.Hilk To be honest I would be rather confused if it would do

                    v1 += v2; -> {a+d, b+e, c+f}
                    

                    A vector is not a number or something, it is a container. Or is it because it is called "vector" and you expect it to behave like a vector in math? :-)

                    https://forum.qt.io/topic/113070/qt-code-of-conduct

                    K J.HilkJ 2 Replies Last reply
                    0
                    • jsulmJ jsulm

                      @J.Hilk To be honest I would be rather confused if it would do

                      v1 += v2; -> {a+d, b+e, c+f}
                      

                      A vector is not a number or something, it is a container. Or is it because it is called "vector" and you expect it to behave like a vector in math? :-)

                      K Offline
                      K Offline
                      koahnig
                      wrote on last edited by
                      #20

                      @jsulm said in C++ % " ?:

                      @J.Hilk To be honest I would be rather confused if it would do

                      v1 += v2; -> {a+d, b+e, c+f}
                      

                      A vector is not a number or something, it is a container. Or is it because it is called "vector" and you expect it to behave like a vector in math? :-)

                      That is debatable and apparently dependent on your background. The foprm you find confusing would be the most logical version for me.

                      Vote the answer(s) that helped you to solve your issue(s)

                      jsulmJ 1 Reply Last reply
                      0
                      • jsulmJ jsulm

                        @J.Hilk To be honest I would be rather confused if it would do

                        v1 += v2; -> {a+d, b+e, c+f}
                        

                        A vector is not a number or something, it is a container. Or is it because it is called "vector" and you expect it to behave like a vector in math? :-)

                        J.HilkJ Online
                        J.HilkJ Online
                        J.Hilk
                        Moderators
                        wrote on last edited by
                        #21

                        @jsulm I used to use only QList as a container, and one day I needed to do Vector operations. In my youthfull naiveté I assumed QVector = linear algebra vector.
                        I learned quickly thats not the case 🤷

                        Ever since, I prefere using QVector over QList.😉


                        Be aware of the Qt Code of Conduct, when posting : https://forum.qt.io/topic/113070/qt-code-of-conduct


                        Q: What's that?
                        A: It's blue light.
                        Q: What does it do?
                        A: It turns blue.

                        1 Reply Last reply
                        0
                        • K koahnig

                          @jsulm said in C++ % " ?:

                          @J.Hilk To be honest I would be rather confused if it would do

                          v1 += v2; -> {a+d, b+e, c+f}
                          

                          A vector is not a number or something, it is a container. Or is it because it is called "vector" and you expect it to behave like a vector in math? :-)

                          That is debatable and apparently dependent on your background. The foprm you find confusing would be the most logical version for me.

                          jsulmJ Offline
                          jsulmJ Offline
                          jsulm
                          Lifetime Qt Champion
                          wrote on last edited by
                          #22

                          @koahnig Yes, that's true.
                          @J-Hilk I'm actually wondering why it is called vector? Something like "QDynamicArray" would be less confusing.

                          https://forum.qt.io/topic/113070/qt-code-of-conduct

                          K kshegunovK 2 Replies Last reply
                          0
                          • jsulmJ jsulm

                            @koahnig Yes, that's true.
                            @J-Hilk I'm actually wondering why it is called vector? Something like "QDynamicArray" would be less confusing.

                            K Offline
                            K Offline
                            koahnig
                            wrote on last edited by
                            #23

                            @jsulm

                            In the mathematical sense it is alwways a vector, but in spaces with different dimensions. All operators are bascially identical, therefore "real" engineers can accept this. Personally I doubt that the definition of basically changing the space dimension during an addition is conform with pure mathematics. On the other hand you never know what they think/thoght in those areas ;)

                            Vote the answer(s) that helped you to solve your issue(s)

                            1 Reply Last reply
                            0
                            • jsulmJ jsulm

                              @koahnig Yes, that's true.
                              @J-Hilk I'm actually wondering why it is called vector? Something like "QDynamicArray" would be less confusing.

                              kshegunovK Offline
                              kshegunovK Offline
                              kshegunov
                              Moderators
                              wrote on last edited by kshegunov
                              #24

                              @jsulm said in C++ % " ?:

                              I'm actually wondering why it is called vector?

                              In linear (and higher) algebra, a vector is an ordered set, or more precisely (and formally speaking) - it is the element of the linear space defined over a field; usually the field of real or complex numbers. Very similar to what you call a vector in programming.

                              It's just convenience that in Qt you have the + defined to mean merging of two arrays, and not the mathematical operation, as you don't regularly require the mathematical properties of a vector; it's just not so useful in everyday life.

                              Read and abide by the Qt Code of Conduct

                              1 Reply Last reply
                              0
                              • J.HilkJ J.Hilk

                                @JonB Qt has ome confusing operaters as well.

                                for example take QVectors +=

                                QVector<T> QVector::operator+(const QVector<T> &other) const
                                

                                I would asume this to be Vector addtion

                                QVector v1{a,b,c};
                                QVector v2{d,e,f};
                                
                                //What one would expect
                                v1 += v2; -> {a+d, b+e, c+f}
                                
                                //what one gets
                                v1 +=v2; _> {a,b,c,d,e,f}
                                

                                I mean, this technically makes sense. QVector is to generic to have this operation, thats why there is QVector2D, 3D, 4D etc

                                It still confused me the first time I used it. I did not expect += to be equal to .append() or <<;

                                In this paticular example I have would prefere a missing += operator :-).

                                JKSHJ Online
                                JKSHJ Online
                                JKSH
                                Moderators
                                wrote on last edited by JKSH
                                #25

                                @J.Hilk said in C++ % " ?:

                                @JonB Qt has ome confusing operaters as well.

                                for example take QVectors +=

                                QVector<T> QVector::operator+(const QVector<T> &other) const
                                

                                I would asume this to be Vector addtion

                                QVector v1{a,b,c};
                                QVector v2{d,e,f};
                                
                                //What one would expect
                                v1 += v2; -> {a+d, b+e, c+f}
                                
                                //what one gets
                                v1 +=v2; _> {a,b,c,d,e,f}
                                

                                I mean, this technically makes sense. QVector is to generic to have this operation, thats why there is QVector2D, 3D, 4D etc

                                It still confused me the first time I used it. I did not expect += to be equal to .append() or <<;

                                In this paticular example I have would prefere a missing += operator :-).

                                Wait till you try + or += on QJsonArray ;)

                                QJsonArray a1{1, 2, 3};
                                QJsonArray a2{4, 5, 6};
                                
                                a1 += a2;
                                // a1 now has 4 elements: 3 numbers and 1 array
                                

                                Qt Doc Search for browsers: forum.qt.io/topic/35616/web-browser-extension-for-improved-doc-searches

                                J.HilkJ 1 Reply Last reply
                                3
                                • JKSHJ JKSH

                                  @J.Hilk said in C++ % " ?:

                                  @JonB Qt has ome confusing operaters as well.

                                  for example take QVectors +=

                                  QVector<T> QVector::operator+(const QVector<T> &other) const
                                  

                                  I would asume this to be Vector addtion

                                  QVector v1{a,b,c};
                                  QVector v2{d,e,f};
                                  
                                  //What one would expect
                                  v1 += v2; -> {a+d, b+e, c+f}
                                  
                                  //what one gets
                                  v1 +=v2; _> {a,b,c,d,e,f}
                                  

                                  I mean, this technically makes sense. QVector is to generic to have this operation, thats why there is QVector2D, 3D, 4D etc

                                  It still confused me the first time I used it. I did not expect += to be equal to .append() or <<;

                                  In this paticular example I have would prefere a missing += operator :-).

                                  Wait till you try + or += on QJsonArray ;)

                                  QJsonArray a1{1, 2, 3};
                                  QJsonArray a2{4, 5, 6};
                                  
                                  a1 += a2;
                                  // a1 now has 4 elements: 3 numbers and 1 array
                                  
                                  J.HilkJ Online
                                  J.HilkJ Online
                                  J.Hilk
                                  Moderators
                                  wrote on last edited by
                                  #26

                                  @JKSH said in C++ % " ?:

                                  Wait till you try + or += on QJsonArray ;)

                                  QJsonArray a1{1, 2, 3};
                                  QJsonArray a2{4, 5, 6};
                                  
                                  a1 += a2;
                                  // a1 now has 4 elements: 3 numbers and 1 array
                                  

                                  😑😔
                                  of course it does.

                                  Not a fan!


                                  Be aware of the Qt Code of Conduct, when posting : https://forum.qt.io/topic/113070/qt-code-of-conduct


                                  Q: What's that?
                                  A: It's blue light.
                                  Q: What does it do?
                                  A: It turns blue.

                                  1 Reply Last reply
                                  1

                                  • Login

                                  • Login or register to search.
                                  • First post
                                    Last post
                                  0
                                  • Categories
                                  • Recent
                                  • Tags
                                  • Popular
                                  • Users
                                  • Groups
                                  • Search
                                  • Get Qt Extensions
                                  • Unsolved