QT SQL query loop?

davethedave

Hey, currently this loop only gets the first username in the table, how can i properly do this so it checks all rows for the username
while (query.next() && query.value("Username").toString().toUtf8().constData() && query.value("Password").toString().toUtf8().constData())
{
printf("Usernames: %s", query.value("Username").toString().toUtf8().constData());

SGaist

Hi,

How many entries do you have in that table ?
What query did you use ?
Why are you doing this complex check in the while condition ?

davethedave

Hello, I have 5 entries
query.exec("SELECT * FROM users");
if (query.size() > 0)

and its the only check i could think of

JonB

@davethedave

query.exec("SELECT * FROM users");
while (query.next())
{
    printf("Usernames: %s", query.value("Username").toString());
}

davethedave

@JonB
Prints first entry in the table still.

JonB

@davethedave
Please show output of each of the 2 following:

query.exec("SELECT COUNT(*) FROM users");
while (query.next())
{
    printf("Number: %s\n", query.value(0).toString());
}

query.exec("SELECT * FROM users");
while (query.next())
{
    printf("Username: %s\n", query.value(0).toString());
}

davethedave

@JonB said in QT SQL query loop?:

query.exec("SELECT * FROM users");

from the first:
http://prntscr.com/khp72u

if i append
.toUtf8().constData() then the below
http://prntscr.com/khp79y

from the second:
http://prntscr.com/khp72u

if i append
.toUtf8().constData() then the below
http://prntscr.com/khp7tw

Also there is only 3 rows now

JonB

@davethedave
Firstly, I don't work in C++ so I don't test the code for the right way to pass the output string to printf(). So your corrections are good. [BTW you'd be better off not using printf() and using Qt/C++ functions, then you wouldn't have all that toUtf8().constData() stuff, but that's another matter.]

As you can see you have 3 rows matching the query, you tell us you have 5, or you had 5 and now you have 3. That's worrying when you're asking for help. Your Username value appears to be 1 from the output. That is a strange username. I don't know what your problem is. The original code should correctly print out whatever is in the Username column of each row encountered (note that since you didn't put a \n in it will all come on one line, which isn't great, I do trust that is not what this is all about.)