[SOLVED] 2 QTableViews data

guidupas

Hello all!

I have a code that create 2 QTableViews dynamically when a QPushButton is clicked:

@
void MainWindow::on_pushButtonNovoInvestimento_clicked()
{
QTableView *tableViewLancamentosInvestimento = new QTableView(boxInvestimento2);
QTableView *tableViewIndicadoresInvestimento = new QTableView(boxInvestimento2);

QStandardItemModel *modeloLancamentosInvestimento = new QStandardItemModel(0, 3, tableViewLancamentosInvestimento);
QStandardItemModel *modeloIndicadoresInvestimento = new QStandardItemModel(0, 2, tableViewIndicadoresInvestimento);

tableViewLancamentosInvestimento->setModel(modeloLancamentosInvestimento);
tableViewIndicadoresInvestimento->setModel(modeloIndicadoresInvestimento);

connect(modeloLancamentosInvestimento, SIGNAL(dataChanged(QModelIndex,QModelIndex)), this, SLOT(alteraModeloLancamentoInvestimento(QModelIndex,QModelIndex)));
}
@

But I need that when data of the first model changes, some data of the second model changes too.

How can I do that once the 2 models are created dynamically?

I am trying to do something like the code above, but its not working:
@
void MainWindow::alteraModeloLancamentoInvestimento(QModelIndex topLeft, QModelIndex bottomRight)
{
QStandardItemModel *modeloLancamentosInvestimento = qobject_cast<QStandardItemModel *>(sender());
}
@

How can I access the second model?

Xander84

I would suggest you just save a reference to the model or the QTableView in your class?!

The sender of a signal is always, well the sender (the button in your case?) and not the model, unless that signals is emitted from your first model I can't tell from the code.
Anyway I would still save a reference to that model or table, why not? it's just a simple pointer :)

guidupas

Hey Xander84!

It worked, thanks a lot.