How to use a specialization of an C++ interface?

[c64zottel]

Very straight forward case, I register like:

qmlRegisterUncreatableType<InputDeviceConfiguratorGate>(
    "InputDeviceConfiguratorGate", 1, 0, "InputDeviceConfiguratorGate", "Not creatable in Qml." );

qmlRegisterUncreatableType<JoystickDeviceConfigurator>(
    "JoystickDeviceConfigurator", 1, 0, "JoystickDeviceConfigurator", "Not creatable in Qml." );

JoystickDeviceConfigurator is derived publicly from InputDeviceConfiguratorGate.

At runtime I get the following error:

QMetaType::registerTypedef: -- Type name 'InputDeviceConfiguratorGate*' previously registered as typedef of 'InputDeviceConfiguratorGate*' [1049], now registering as typedef of 'JoystickDeviceConfigurator*' [1051].

I actually would like to have InputDeviceConfiguratorGate registered as interface. The question was asked
here.

[c64zottel]

@c64zottel Ok, I figured it out. My mistake is a missing Q_OBJECT declaration in the JoystickDeviceConfigurator:

class JoystickDeviceConfigurator : public InputDeviceConfiguratorGate
{
    Q_OBJECT
public: