Solved QMetaObject problem with QPushButton connection
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In the .h file for my class, I define a QPushButton as well as the function that will be called. It looks like this:
private slots:
void on_bubbleTypeButton_clicked();private:
QPushButton *bubbleTypeButton;Then in the constructor for the class, I create the button with this code:
bubbleTypeButton = new QPushButton(this); bubbleTypeButton->setGeometry(400, 168, 250, 40); connect(bubbleTypeButton, SIGNAL(clicked()), this, SLOT(on_bubbleTypeButton_clicked()));
The code compiles fine, but when I run the code, I get the following message:
QMetaObject::connectSlotsByName: No matching signal for on_bubbleTypeButton_clicked()When I click the button, the on_bubbleTypeButton_clicked function runs, but obviously I don't want the error message. What did I miss?
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hi and welcome
Qt has a auto connect feature that trigger via naming. on_widgetname_signal syntax.
Since you are using a manual connect, please try to rename
slot so its not on_xxx syntax.
Then clean build folder.
run qmake
and rebuild all.
That normally shut it up :) -
Yes, that did it. Thanks