[Solved]Why my defined QAction has no response?

Sam

Hi ,

Welcome to DEVNET,

If you check line 16 of mainwindow.cpp I think there is a mistake with

@this->connect(rgbFilterAct,SIGNAL(triggereed()),this,SLOT(filterRGB()));@

triggered() should be used ,spelling mistake/ you dont have any SIGNAL : triggereed() declaration for RGBDlg.

Sam

[quote author="gayu" date="1353394688"]Think so u r using Qt4. Whether the code runs fine without showing any errors?
I checked the code whether it is running or not.
But,the code works fine for me.[/quote]

The Project compiles n Runs successfully but for him the QAction is not working . Did you check with the requirements as I see if you click on Processing->Filter RGB it does not open RGBDlg, as there is a spelling mistake for the SIGNAL that he/she is trying to connect.

gayu

Whether the QAction is not working for him

mybiandou

Thank you, Sam

You are quire right.

I am sorry for my silly problem. It confused me for a week.

I really wish the meta object compiler can help much.

Sam

You are welcome,

bq. I am sorry for my silly problem.

No need, we all are here to learn :)

Kindly Edit your first post and prepend [Solved] to the title.

Happy Coding !!

gayu

In my project i also used the same QAction, but when compiling it show some errors.
Thats y i asked u about the QAction. Will u please tell me about that

Sam

[quote author="gayu" date="1353399435"]In my project i also used the same QAction, but when compiling it show some errors.
Thats y i asked u about the QAction. Will u please tell me about that[/quote]

What errors are you getting ?

gayu

ERROR
no matching function for call to ‘QAction::QAction(QString, QPixmap, QString, unsigned int, mainForm* const, const char [8])’

Sam

And how are you connecting the signals and slots ? Kindly share your code .

gayu

Ya sure
The following is the main.cpp file

@
#include <qapplication.h>
#include "mainform.h"

int main( int argc, char ** argv )
{
QApplication a( argc, argv );
mainForm w;
w.show();
a.connect( &a, SIGNAL( lastWindowClosed() ), &a, SLOT( quit() ) );
return a.exec();
}
@
The following code is somewhere in the mainform.cpp file

@
void mainForm::setupLanguageActions()
{

Q3ToolBar *tb = new Q3ToolBar( this );
tb->setLabel( "Language Actions" );
Q3PopupMenu *menu = new Q3PopupMenu( this );
menuBar()->insertItem( tr( "&Language" ), menu );

Q3Action *a;
a = new Q3Action( tr( "Tamil" ), tr( "&Tamil" ), Qt::CTRL + Qt::Key_Z, this, "langtamil" );
connect( a, SIGNAL( activated() ), this, SLOT( ChangeLangTamil() ) );
a->addTo( tb );
a->addTo( menu );

a = new Q3Action( tr( "Hindi" ), tr( "&Hindi" ), Qt::CTRL + Qt::Key_Y, this, "langhindi" );
connect( a, SIGNAL( activated() ), this, SLOT( ChangeLangHindi() ) );
a->addTo( tb );
a->addTo( menu );

}
@
And also for more actions..

Sam

Are you including the proper header files , Try including QObject header and build.
Also check for the proper signature of Q3Action class .

gayu

Might what the question i'm asking is silly, but please tell me
Whether Qt4 support QAction

Sam

[quote author="gayu" date="1353403125"]Might what the question i'm asking is silly, but please tell me
Whether Qt4 support QAction[/quote]

Ofcourse Qt4 support QAction ,you can have a look in "Porting to Qt 4":http://qt-project.org/doc/qt-4.8/porting4.html#qaction and "QAction":http://qt-project.org/doc/qt-4.8/qaction.html class.

But why are you still working in Qt 3 ?

gayu

So when using Q3ToolBar and Q3PopupMenu, their actions must be Q3Actions.
Otherwise the QAction itself is used right.