[UI] Connection between QAction and SLOT

lowee

Hi everybody,

I've already made a Qt UI with Qt Designer and I got a menu bar with File menu (New File, Open File, Save File, Quit).

My wish is to connect the Quit action when its triggered to quit ... I tried the command

@connect(Ui_MainWindow.actionQuit, SIGNAL(triggered()), this, SLOT(close()));@

in the constructor of MainWindow but i got this error message :
@..\mainwindow.cpp: In constructor 'MainWindow::MainWindow(QWidget*)':
..\mainwindow.cpp:10: error: expected primary-expression before '.' token@

I don't really understand this error ...

So I tried with the UI connection action ("go to slot") it works but i just want to know if it's possible to make this connection and if it is possible how (because with the ui connection action, i will get too much functions...) ?

Hostel

Paste more code. What type is Ui_MainWindow? Where you declare actions? This could be a problem with include(missing include) or not. Hard to say without a context.

qxoz

If you want create menu by yourself you must create an action and then bin them with Slot and menu item.

Something like that:
@
void MainWindow::createActions()
{
newAction = new QAction(tr("&New"), this);
newAction->setIcon(QIcon(":/images/new.png"));
newAction->setShortcut(tr("Ctrl+N"));
newAction->setStatusTip(tr("Create a new spreadsheet file"));
connect(newAction, SIGNAL(triggered()), this, SLOT(newFile()));

@

adding menu item
@
fileMenu = menuBar()->addMenu(tr("&File"));
fileMenu->addAction(newAction);
@

qxoz

but if you want use already created Actions:

@connect(ui->actionName, SIGNAL(triggered()), this, SLOT(on_triggered()));
@

lowee

Thanks a lot qxoz, I'll create the entire interface including the menu item.

If I have some problems, I'll post them in this post...