QPushButton to activate widget.show()

[sheehan1234]

does anyone know why this won't work?

@QObject::connect(button, SIGNAL(clicked()), widget, SLOT(show());@

button is my QPushButton
I'm trying to perform the operation; widget.show() whenever it gets clicked

[picasoft]

What the base class of your widget?

[Eddy]

Is widget available in the scope?

Where did you put the connect?

[sheehan1234]

widget is available, this is in my main method. i have previous calls to widget in the main. I originally had "widget.show();" which worked properly. I'm trying to add a button that will make it happen.

[Eddy]

Where did you put your button?

[sheehan1234]

also in the main

[Eddy]

Can you show your main then? I suspect you didn't put the button in a dialog or mainwindow. How do you show your button so you can click it?

[sheehan1234]

@int main(int argc, char *argv[])
{
QApplication app(argc, argv);
MyWidget widget;
widget.betaNum = 20;

QWidget *win = new QWidget;
QVBoxLayout *layout = new QVBoxLayout;
QComboBox *combo = new QComboBox;
QPushButton *button = new QPushButton("Plot");
combo->addItem("1");
combo->addItem("2.000001");
combo->addItem("4");
layout->addWidget(combo);
layout->addWidget(button);
win->setLayout(layout);
win->show();
widget.stabreg = combo->itemData(combo->currentIndex()).toFloat();

QObject::connect(button, SIGNAL(clicked()), widget, SLOT(show());

return app.exec();

}@

I have two widgets, one is the graph (widget) and the second one (win) is the one with a drop down menu

[Eddy]

Why don't you use a QDialog instead of QWidget? A QWidget is meant to be used in another window not as a popup.

[goetz]

connect() takes object pointers (adresses) as arguments. As your widget is stack based, you need operator & to pass an address, so just change widget to &widget in the statement:

@
// WRONG
QObject::connect(button, SIGNAL(clicked()), widget, SLOT(show());

// right
QObject::connect(button, SIGNAL(clicked()), &widget, SLOT(show());
@