How can i get pointer on the widget of current tab in QTabWidget?

[Ruzik]

I read it before i asked, but on the this code
@ tabWidget->addTab(new QPlainTextEdit, "New tab");
QPlainTextEdit * p = qobject_cast<QPlainTextEdit *>(tabWidget->currentWidget());
p->setPlainText("dsg");@
Compiler get me a error, and thats why i asked you about it

[giesbert]

which error?

[Ruzik]

If i change code:
@ tabWidget->addTab(new QPlainTextEdit, "New tab");
QPlainTextEdit * p = qobject_cast<QPlainTextEdit *>(tabWidget->currentWidget());
if (p)
p->setPlainText("dsg");@
It is work right, but conversion does not occur

[Ruzik]

[quote author="Gerolf" date="1308252787"]which error?[/quote]
Access violation when reading

[giesbert]

is the new tab the current one? are you sure?

[ludde]

A bit hard to see what's wrong from just those four lines of code.
I assume qssTextEdit is a QPlainTextEdit subclass?
And that you haven't added any other tabs?
You could always check what tabWidget->currentWidget() actually returns, using a debugger or some form of debug output, e.g. by printing what tabWidget->currentWidget()->metaObject()->className() returns.

[Ruzik]

Many thanks for your help - i find error!

[mlong]

What was it? (For those of us who are keeping score...)

[Ruzik]

I'm in the designer created a table and a default is already located there QPlainTextEdit and when I addressed him, it is transformed into kvidget, not QPlainTextEdit

[Qlearner]

To read the text associated with a tab's QTextEdit widget ( tab at index x) , I did this
@ tabWidget->addTab(new QTextEdit ,"New tab");
QTextEdit* t= qobject_cast<QTextEdit*>(tabWidget->widget(x));
qDebug() << t->toPlainText();
@

Just in case someone still needed it.

[vittalonline]

Hi.. Ruzik

once try this code..

QTabWidget *wd;
tabWidget->addTab(new QTextEdit ,"New tab");

QList<QTextEdit * > widgets = wd->findChildren<QTextEdit* >();
.....

widgets.at(2) or widgets.at(index)