Utiliser une commande lambda avec connect

Futuray Programming

Bonjour,
j'essaye d'utiliser un QOject::connect pour modifier une variable de type int :

QObject::connect(bouton, SIGNAL(clicked()), this, [this](){
  variable++;
});

Or, cela me sort plusieurs erreurs :

no matching function for call to ‘OptionMenuView::connect(QPushButton*&, const char*, vue*, vue::vue(QWidget*)::<lambda(int)>)’
      |     });
      |      ^

et

erreur : no type named ‘Object’ in ‘struct QtPrivate::FunctionPointer<OptionMenuView::OptionMenuView(QWidget*)::<lambda(int)> >’
In file included from /home/-/Qt/6.4.1/gcc_64/include/QtWidgets/qgraphicsitem.h:8,
                 from /home/-/Qt/6.4.1/gcc_64/include/QtWidgets/QGraphicsItem:1,
                 from /home/-/-/rpg/main/optionmenuview.h:4,
                 from /home/-/-/rpg/main/optionmenuview.cpp:1:
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:181:36: note: candidate: ‘static QMetaObject::Connection QObject::connect(const QObject*, const char*, const QObject*, const char*, Qt::ConnectionType)’
  181 |     static QMetaObject::Connection connect(const QObject *sender, const char *signal,
      |                                    ^~~~~~~
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:182:62: note:   no known conversion for argument 4 from ‘OptionMenuView::OptionMenuView(QWidget*)::<lambda(int)>’ to ‘const char*’
  182 |                         const QObject *receiver, const char *member, Qt::ConnectionType = Qt::AutoConnection);
      |                                                  ~~~~~~~~~~~~^~~~~~
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:184:36: note: candidate: ‘static QMetaObject::Connection QObject::connect(const QObject*, const QMetaMethod&, const QObject*, const QMetaMethod&, Qt::ConnectionType)’
  184 |     static QMetaObject::Connection connect(const QObject *sender, const QMetaMethod &signal,
      |                                    ^~~~~~~
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:184:86: note:   no known conversion for argument 2 from ‘const char*’ to ‘const QMetaMethod&’
  184 |     static QMetaObject::Connection connect(const QObject *sender, const QMetaMethod &signal,
      |                                                                   ~~~~~~~~~~~~~~~~~~~^~~~~~
/home/sit/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:432:32: note: candidate: ‘QMetaObject::Connection QObject::connect(const QObject*, const char*, const char*, Qt::ConnectionType) const’
  432 | inline QMetaObject::Connection QObject::connect(const QObject *asender, const char *asignal,
      |                                ^~~~~~~
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:433:57: note:   no known conversion for argument 3 from ‘OptionMenuView*’ to ‘const char*’
  433 |                                             const char *amember, Qt::ConnectionType atype) const
      |                                             ~~~~~~~~~~~~^~~~~~~
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:201:43: note: candidate: ‘template<class Func1, class Func2> static QMetaObject::Connection QObject::connect(const typename QtPrivate::FunctionPointer<Func>::Object*, Func1, const typename QtPrivate::FunctionPointer<Func2>::Object*, Func2, Qt::ConnectionType)’
  201 |     static inline QMetaObject::Connection connect(const typename QtPrivate::FunctionPointer<Func1>::Object *sender, Func1 signal,
      |                                           ^~~~~~~
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:201:43: note:   template argument deduction/substitution failed:
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h: In substitution of ‘template<class Func1, class Func2> static QMetaObject::Connection QObject::connect(const typename QtPrivate::FunctionPointer<Func>::Object*, Func1, const typename QtPrivate::FunctionPointer<Func2>::Object*, Func2, Qt::ConnectionType) [with Func1 = const char*; Func2 = OptionMenuView::OptionMenuView(QWidget*)::<lambda(int)>]’:
/home/-/nicolas/rpg/main/optionmenuview.cpp:33:6:   required from here
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:201:43: error: no type named ‘Object’ in ‘struct QtPrivate::FunctionPointer<OptionMenuView::OptionMenuView(QWidget*)::<lambda(int)> >’
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:233:13: note: candidate: ‘template<class Func1, class Func2> static typename std::enable_if<((int)(QtPrivate::FunctionPointer<Func2>::ArgumentCount) >= 0), QMetaObject::Connection>::type QObject::connect(const typename QtPrivate::FunctionPointer<Func>::Object*, Func1, Func2)’
  233 |             connect(const typename QtPrivate::FunctionPointer<Func1>::Object *sender, Func1 signal, Func2 slot)
      |             ^~~~~~~
/home/-/Qt/6.4.1/gcc_64/include/QtCore/qobject.h:233:13: note:   template argument deduction/substitution failed:
/home/-/-/-/main/optionmenuview.cpp:33:6: note:   candidate expects 3 arguments, 4 provided
      |     });
      |      ^

et encore 2 autres très similaires.
Si quelqu'un peut m'aider, je le remercie d'avance.

JonB

@Futuray-Programming
On ne peut pas avoir SIGNAL/SLOT() macros avec le connect() moderne qui permet un lambda:

QObject::connect(bouton, &QPushButton::clicked, this, [this](){

~~Ne utilisez plus le syntaxe ancien avec les macros.~~
N'utilisez plus l'ancienne syntaxe avec les macros.

mpergand

@Futuray-Programming said in Utiliser une commande lambda avec connect:

QObject::connect(bouton, SIGNAL(clicked()), this, this{
variable++;
});

Essaye avec la nouvelle syntaxe:

connect(bouton, &QPushButton::clicked, this, [this](){
  variable++;
});

JonB

@Futuray-Programming
On ne peut pas avoir SIGNAL/SLOT() macros avec le connect() moderne qui permet un lambda:

QObject::connect(bouton, &QPushButton::clicked, this, [this](){

~~Ne utilisez plus le syntaxe ancien avec les macros.~~
N'utilisez plus l'ancienne syntaxe avec les macros.

mpergand

@JonB said in Utiliser une commande lambda avec connect:

Ne utilisez plus le syntaxe ancien avec les macros.

En bon français:
N'utilisez plus l'ancienne syntaxe avec les macros.
:)

JonB

@mpergand Soupir :) Merci, je l'ai corrigé

Futuray Programming

Ah oui, en effet, je ne connaissais pas la nouvelle syntaxe.
Je vais mètre à jour tout le code du coup.
👍

mpergand

@Futuray-Programming said in Utiliser une commande lambda avec connect:

Je vais mètre à jour tout le code du coup.

Combien de mètres de code ? :)

Futuray Programming

@mpergand Ah, oui oups...
😑

GrecKo

Nouvelle syntaxe qui a 10 ans pour info ;)