Four-finger swipe on iPad

[Phuoc Nguyen]

Dear all experts!
I am developing an application for Android/iOS.
I am using MouseArea to make my button.
I am stuck in the following case:
Touch on screen with 4 fingers, 1 finger among them touch on the button.
Swipe the screen.
The application become inactive state. I display a item as a popup (the button will go into disable state) when the application become active state again. Then the popup will be hidden, the button is enable state.
Now the button doesn't receive mouse event again.
Are there any hint?
Thanks you for help
Best regards

[Phuoc Nguyen]

Luckily, I can resolve my problem. I override notify method of QGuiApplication:

bool MyApplication::notify(QObject *receiver, QEvent *event){
    QEvent::Type t = event->type();
    switch(t){
    case QEvent::MouseButtonPress:
        lastReceiver = receiver;
        break;
    case QEvent::MouseButtonRelease:
        lastReceiver = NULL;
        break;
    case QEvent::ApplicationStateChange:
        //To background
        if (lastReceiver != NULL){
            QQuickItem*item = qobject_cast< QQuickItem*>(lastReceiver);
            if (item != NULL){
                if(QGuiApplication::applicationState() == Qt::ApplicationInactive){
                    item ->ungrabMouse();
                }
                if(QGuiApplication::applicationState() == Qt::ApplicationActive ){
                    item ->grabMouse();
                    lastReceiver = NULL;
                }
            }
        }

        break;
    default:
        break;
    }
    return QGuiApplication::notify(receiver,event);
}

In the above piece of code, lastReceiver is a private variable. It is used to keep the last mouse pressed event object