Avoid that a QDialog activates with show()

floatingWoods

Hello,
I have an application that is a main window, which can have several QDialogs as children (always in front). When I create and show such a child QDialog, it activates (i.e. it gets the mouse and keyboard focus/input, which is normal). However, I would prefer to have the QDialog not activate, since I still need the keyboard focus on the main window.
So what I am currently doing is:

childDialog->show();
mainWindow->activateWindow();

But I feel this is not the correct way of doing. Is there a way to show a QDialog without having it activated automatically?
Thanks for any information

Chris Kawa

There's an attribute for that. Somewhere before showing the dialog call setAttribute(Qt::WA_ShowWithoutActivating) on it.

mpergand

An option could be to add the Qt::WindowDoesNotAcceptFocus flags attributs of your dialog,
if your dialog doesn't have any line or text edit.

floatingWoods

Thanks for the quick reply. My Dialogs have actually those line widgets, etc. They are more like contextual tool window, that pop open if a certain object is selected in the main window. The User will very probably continue to work in the main window, but if he/she clicks on the child dialog, he/she can change the selected object's properties.

Chris Kawa

There's an attribute for that. Somewhere before showing the dialog call setAttribute(Qt::WA_ShowWithoutActivating) on it.

floatingWoods

That's just perfect! How could I oversee this?
Thanks a lot!