Unsolved Find if a shell file exists

[Sylas]

@Sylas Look please at the commented line "ifstream". Uncomment that and you'll see computer return ERROR

[mrjj]

but what was the error`?
The compiler actually tells you what is wrong.
So to be a programmer, u MUST care for what it says. :)

I think it just a case of NOT right type?
ifstream monFlux(total);

here you gives it a std::string
total is a std::string, yes?
does it expect that?

maybe
ifstream monFlux(total.c_str());
will make it more happy?

[Sylas]

@mrjj It runs well but the if statement is always "inexistant file". The compiler says: Checking for existance: /home/sylvain/ESSAI/bin/Release/ESSAI.
ESSAI is the name of the project (Code:Blocks), but the name of the file is essai.
essai really exists as a shell file. Thanks again, because now we go forth

[mrjj]

and the file is there
"/home/sylvain/essai" ?

im not sure your code can actually check if file exits since you just create the
stream object but dont really use it.

maybe try
ifstream a_file ( "/home/sylvain/essai" );

if ( !a_file.is_open() ) {
cout << "fichier inexistant." << endl;
}
else {
cout << "Ce fichier existe\n";
}

[Sylas]

@mrjj I tried your little program. It runs but, unfortunately, gives always the same answer: "ce fichier existe", even if it is not true.

[Sylas]

@mrjj Excuse me. Your litte program works very well. I did the mistake to not replace essai by an other file (inexistent), inside your little program.

[mrjj]

ok that sounds good. :)
a_file.is_open() should only be true when it can actually open the file. (it exists)

[Sylas]

@mrjj I tried that: ifstream a_file("/home/sylvain/" <<shell<<'"'); The compiler says: error no match for 'oprator <<' (operand types are 'const char [15] and 'std::string {aka std::basic_string<char>}')
As I am a beginner that is chinese for me, but for you it is different.

[mrjj]

@Sylas said:

a_file("/home/sylvain/" <<shell<<'"');

this syntax is not valid.
you cannot use << this way.

you would do something like

string filename;
cin >> filename;
string path="/home/sylvain/";
string fullpath=path+filename;
fstream a_file (fullpath );
if ( !a_file.is_open() ) {
....

[Sylas]

@mrjj May be the solution is much more simple. I tried that:
cout << "rentrez nom du fichier\n";
string a_file;
cin >> a_file;

if ( !a_file.is_open() ) {
cout << "fichier inexistant." << endl;
}
else {
cout << "Ce fichier existe\n";
}
My new error is: 'std::string' has no member named 'is_open'
What do you think of that ? ? Many thanks

[mrjj]

hi
The open function belong to fstream class
and in this case the compiler is very clear :)

'std::string' has no member named 'is_open'

Which means that
string a_file; <---- its a string
do not have such function.

fstream has it
http://www.cplusplus.com/reference/fstream/ifstream/is_open/

so it will never work.