Casting a auto_ptr<QWidget> to QWidget
sunil.nair last edited by
Hi I am trying to cast a auto_ptr<QWidget> to a QWidget. I have tried multiple things : including
QWidget widget=static_cast<auto_ptr<QWidget> >(nativeWidget);
It gives me an error that std::auto_ptr<QWidget> cannot be cast as a QWidget.
How can I cast it?
Since QWidget derives from QObject, there are no assignment/copy operators available. You need to use only pointer types (unless you construct it on the stack)
anyway, there is no need to do a cast in your case:
QWidget* widget = nativeWidget.get(); // or use release(); read the docs to see what is more applicable for your usecase
bsomervi last edited by bsomervi
If you have C++11 capabilities then you are better using
std::auto_ptr<T>is deprecated. That too has
std::unique_ptr<T>::get()to access the raw pointer and
std::unique_ptr<T>::release()to take over ownership of the object pointed to.