Casting a auto_ptr<QWidget> to QWidget
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Hi I am trying to cast a auto_ptr<QWidget> to a QWidget. I have tried multiple things : including
std::auto_ptr<QWidget> nativeWidget;
QWidget widget=static_cast<auto_ptr<QWidget> >(nativeWidget);It gives me an error that std::auto_ptr<QWidget> cannot be cast as a QWidget.
How can I cast it? -
Hi I am trying to cast a auto_ptr<QWidget> to a QWidget. I have tried multiple things : including
std::auto_ptr<QWidget> nativeWidget;
QWidget widget=static_cast<auto_ptr<QWidget> >(nativeWidget);It gives me an error that std::auto_ptr<QWidget> cannot be cast as a QWidget.
How can I cast it?@sunil.nair
Since QWidget derives from QObject, there are no assignment/copy operators available. You need to use only pointer types (unless you construct it on the stack) -
Hi I am trying to cast a auto_ptr<QWidget> to a QWidget. I have tried multiple things : including
std::auto_ptr<QWidget> nativeWidget;
QWidget widget=static_cast<auto_ptr<QWidget> >(nativeWidget);It gives me an error that std::auto_ptr<QWidget> cannot be cast as a QWidget.
How can I cast it?@sunil.nair
anyway, there is no need to do a cast in your case:QWidget* widget = nativeWidget.get(); // or use release(); read the docs to see what is more applicable for your usecase -
If you have C++11 capabilities then you are better using
std::unique_ptr<T>,std::auto_ptr<T>is deprecated. That too hasstd::unique_ptr<T>::get()to access the raw pointer andstd::unique_ptr<T>::release()to take over ownership of the object pointed to.
