<![CDATA[Casting a auto_ptr<QWidget> to QWidget]]>Hi I am trying to cast a auto_ptr<QWidget> to a QWidget. I have tried multiple things : including

std::auto_ptr<QWidget> nativeWidget;
QWidget widget=static_cast<auto_ptr<QWidget> >(nativeWidget);

It gives me an error that std::auto_ptr<QWidget> cannot be cast as a QWidget.
How can I cast it?

]]>https://forum.qt.io/topic/63451/casting-a-auto_ptr-qwidget-to-qwidgetRSS for NodeThu, 07 May 2026 13:15:14 GMTThu, 28 Jan 2016 08:29:45 GMT60<![CDATA[Reply to Casting a auto_ptr<QWidget> to QWidget on Thu, 28 Jan 2016 12:28:32 GMT]]>If you have C++11 capabilities then you are better using std::unique_ptr<T>, std::auto_ptr<T> is deprecated. That too has std::unique_ptr<T>::get() to access the raw pointer and std::unique_ptr<T>::release() to take over ownership of the object pointed to.

]]>https://forum.qt.io/post/310065https://forum.qt.io/post/310065Thu, 28 Jan 2016 12:28:32 GMT<![CDATA[Reply to Casting a auto_ptr<QWidget> to QWidget on Thu, 28 Jan 2016 09:02:27 GMT]]>@sunil.nair
anyway, there is no need to do a cast in your case:

QWidget* widget = nativeWidget.get(); // or use release(); read the docs to see what is more applicable for your usecase
]]>https://forum.qt.io/post/310026https://forum.qt.io/post/310026Thu, 28 Jan 2016 09:02:27 GMT<![CDATA[Reply to Casting a auto_ptr<QWidget> to QWidget on Thu, 28 Jan 2016 08:54:08 GMT]]>@sunil.nair
Since QWidget derives from QObject, there are no assignment/copy operators available. You need to use only pointer types (unless you construct it on the stack)

]]>https://forum.qt.io/post/310017https://forum.qt.io/post/310017Thu, 28 Jan 2016 08:54:08 GMT