[solved] QString to QByteArray

deleted28

Hi,

what is the most efficient (speed) way to convert a QString
@"AA 0D 00 FF 0A 00 00 00 FF FF FF FF 00 00"@

(including SPACEs )

to a QByteArray conatinig the above data as:

@0xAA, 0x0D, 0x00, .... , 0xFF, 0x00, 0x00 @

thx

SGaist

Hi,

You'll have to do some benchmarking.

@
QRegularExpression rx("([A-F0-9]{2})");
text.replace(rx , "0x\1," ).chop(1);
qDebug() << text.toLatin1();
@

is a possibility

[edit: updated code to avoid strange replacement]

deleted28

Hello SGaist,

your suggestion looks faster than mine, but i can not use it as it.
Got @error: 'QRegular' was not declared in this scope@
I included
@#include <QRegularExpression>
#include <QRegExp>

... QRegular[removed] ... // <
@

here is my first trial:
@ int i;
QByteArray ba_frag;
for(i=0;i<text1.size();i+=3) {
ba_frag.append(QByteArray::fromHex((text1.mid(i,2)).toLatin1()));
}
@
above seems to work

JKSH

Hi,

fromHex() already handles spaces. Just call
@
QByteArray ba_frag = QByteArray::fromHex(text1.toLatin1());
@

[quote author="SGaist" date="1424034271"]
@
text.replace(QRegular[removed]"([A-F0-9]{2})"), "0x\1,").chop(1);
@
[/quote]Did the forum censor you??

SGaist

It seems that Expression followed by ( triggers [removed]

deleted28

hm, ?

JKSH

[quote author="wally123" date="1424157850"]hm, ?[/quote]SGaist typed
@
QRegularExpressionn("([A-F0-9]{2})")
// Remove the extra 'n' above
@

but it got converted to...
@
QRegular[removed]"([A-F0-9]{2})")
@
...by forum security.

deleted28

Ah, ok :)