QRegularExpression Problem

  • I am trying a simple pattern to extract numbers from a ASCII text file. The code I am using

    QTextStream in( &file );
    QString line = in.readline();
    QRegularExpression re;
    re.setPattern ( " -?[0-9]+\.?[0-9]* ");
    line.section(re, 0);

    a testing line was:
    "Expected Vibration Frequency = 2.52 MHz"

    Using RegexBuddy I tested the pattern and the results were

    However, when I implement the above code I get
    2.52 Mhz

    I tried the Qt expression of -?\d*\.?\d* and got the same thing. Why are the ascii characters after the digits included?

  • Moderators

    welcome to devnet

    My guess is that the syntax handling used is different. You need to check the documentation of "QRegularExpression":http://qt-project.org/doc/qt-5/qregularexpression.html

    I have never used it. It has been implemented for Qt5. The older version "QRegExp":http://qt-project.org/doc/qt-5/QRegExp.html is also still available.There you have different possibilities.

    The "example code for QRegExp":http://qt-project.org/doc/qt-5/qtwidgets-tools-regexp-example.html is a handy tool to check different possibilities. Unfortunately, it is still based on the older QRegExp.

  • Lifetime Qt Champion

    Hi and welcome to devnet,

    I'd say you are using the wrong tool:

    QString line("Expected Vibration Frequency = 2.52 MHz");
    QRegularExpression re;
    re.setPattern ( "-?[0-9]+\.?[0-9]*");
    QRegularExpressionMatch match = re.match(line);
    qDebug() << match.captured();

    And you'll get 2.52

    Hope it helps

  • Thanks for the help. I had not tried to use the QRegularExpressionMatch. Changing code as your example showed solved the problem.


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