[Solved] Virtual void QTableWidget::setModel(QAbstractItemModel*) is private What i do wrong?

nickvan86

Hello,

i have a problem with this Code:

@QString userEmp = Settings::getUserEmp();
Database data;
if(!data.db1Open())
QMessageBox::critical(this,"Error","Fehler beim öffnen der Datenbank");
else
{
QSqlQuery *qry = new QSqlQuery(data.db1);
QSqlQueryModel *model = new QSqlQueryModel();
qry->prepare("SELECT * FROM messageControl WHERE Empfänger = '"+userEmp+"'");
if(qry->exec())
{
model->setQuery(*qry);
ui->receivedTableWidget->setModel(model);

        data.db1Close();

    }
    else
        QMessageBox::critical(this,"Error",qry->lastError().text());
}@

I have copy the Code from the the same program and paste it in the other Signal. But the Compiler have a problem with this code.

'virtual void QTableWidget::setModel(QAbstractItemModel*)' is private
and
within this context
@ui->receivedTableWidget->setModel(model);@

But the other code is right and this code not. What is the problem?

I hope somebody can help me.

Bye Alex from Germany

SGaist

Hi,

Use a QTableView, QTableWidget has it's own internal model

nickvan86

Thanks. It´s works