[solved] Addition of Float does not give precise result

  • Hi,

    I am doing addition of prices in my application. I have values as QStrings and I convert to float and add. When it reaches high value, result is not precise. I read like float or double should not be used for currency addition and use separate variable for integer part and fractional part. My code and log is below:

    @ qDebug ("m_totalPrice: %f + %f =", m_totalPrice, item.price.toFloat());
    m_totalPrice += item.price.toFloat();
    qDebug ("m_totalPrice: %f", m_totalPrice);
    ui->totalLabel->setText(QString::number(m_totalPrice, 'f', 2));

    m_totalPrice is float and item.price is QString


    m_totalPrice: 424659.500000 + 22350.500000 =

    m_totalPrice: 447010.000000

    m_totalPrice: 447010.000000 + 18.900000 =

    m_totalPrice: 447028.906250

    m_totalPrice: 447028.906250 + 125.900002 =

    m_totalPrice: 447154.812500

    m_totalPrice: 447154.812500 + 125.900002 =

    m_totalPrice: 447280.718750

    m_totalPrice: 447280.718750 + 11.500000 =

    m_totalPrice: 447292.218750

    m_totalPrice: 447292.218750 + 22.500000 =

    m_totalPrice: 447314.718750

    Error is from line 2. Can someone tell how to resolve this?

  • Hi,

    float is a 32bit data type with 8 precision digits; you need more precision so you must use double (16 precision digits) or long double (24 precision digits).

    PS: long double precision depends on the platform

  • Thanks all,

    using double solved the issue

  • [quote author="Abin" date="1403934198"]Thanks all,

    using double solved the issue[/quote]

    Not quite. The issue is still there, hiding from you. As your numbers cannot be represented exactly as base-2 floating point numbers, you will always have rounding errors, and eventually that may still affect your computation. The correct solution is to use integer arithmetic on cents.

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