<![CDATA[[solved] 'invalid conversion' issue]]>Hi,
I am having a 'invalid conversion' that I don't understand:

Function:
@void LongToAsciiQbArrayLeadZ(QByteArray * cAscii, ulong lLongVal, char cNbr)
{
while(cNbr--)
{
cAscii[cNbr] = (char)((lLongVal ) + '0');
lLongVal /= 10;
}
}
@

Call:
@QByteArray qbTempArray;
LongToAsciiQbArrayLeadZ(&qbTempArray, uLogCounter.l++, 10);@

leads to:
Warnung:array subscript has type 'char'
Fehler:invalid conversion from 'char' to 'const char*'

I just don't get what's wrong?
Same works in native C with char array instead of QByteArray.
Thanks, McL

]]>https://forum.qt.io/topic/41141/solved-invalid-conversion-issueRSS for NodeThu, 11 Jun 2026 13:09:15 GMTThu, 08 May 2014 09:03:18 GMT60<![CDATA[Reply to [solved] 'invalid conversion' issue on Thu, 08 May 2014 11:51:51 GMT]]>Works a treat! Thanks :)

]]>https://forum.qt.io/post/227755https://forum.qt.io/post/227755Thu, 08 May 2014 11:51:51 GMT<![CDATA[Reply to [solved] 'invalid conversion' issue on Thu, 08 May 2014 09:39:36 GMT]]>Hi,

try modifying the code like this
@
void LongToAsciiQbArrayLeadZ(QByteArray &cAscii, ulong lLongVal, char cNbr)
{
while(cNbr--)
{
cAscii[cNbr] = (char)((lLongVal ) + '0');
lLongVal /= 10;
}
}
@

@
QByteArray qbTempArray;
LongToAsciiQbArrayLeadZ(qbTempArray, uLogCounter.l++, 10);
@

You used a QByteArray pointer.

]]>https://forum.qt.io/post/227729https://forum.qt.io/post/227729Thu, 08 May 2014 09:39:36 GMT