[SOLVED] From QVariant to QList<QUrl>
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Hi,
I have a QVariant and I need to convert it into a QList<QUrl>. I tried 2 methods:
Convert the QVariant to QList<QUrl> directly => does NOT work;
Iterating over the QVariant and reconstruct the QList<QUrl> "manually" => does work.
CONVERSION
I tried this:@
// Getting QVariant fileUrlsVariant from "somewhere"
std::string typeName = fileUrlsVariant.typeName();
qDebug() << typeName.c_str();
bool convertToUrls = fileUrlsVariant.canConvert<QList<QUrl>>();
qDebug() << convertToUrls;
bool convertToQVariants = fileUrlsVariant.canConvert<QList<QVariant>>();
qDebug() << convertToQVariants;
QList<QVariant> variants = fileUrlsVariant.toList();
qDebug() << variants;
@The output is:
@QList<QUrl>
true
true
() @While it seems i can convert from the QVariant to a QList<QVariant>, doing so results in an empty list. Why that?
ITERATE + CONSTRUCT
@// Getting QVariant fileUrlsVariant from "somewhere"
QSequentialIterable IT = fileUrlsVariant.value<QSequentialIterable>();
QList<QUrl> fileUrls;
for (const QVariant &v : IT)
{
fileUrls.append(v.toUrl());
}
qDebug() << fileUrls;@The output is:
@(QUrl("file:///D:/TEMP/file1.txt") , QUrl( "file:///D:/TEMP/file2.txt" ) , QUrl( "file:///D:/TEMP/file3.txt" ) ) @So here, it seems to work. But I would prefer a method converting the QVariant instead of having to iterate it. Any idea?
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You are using wrong method for getting your list. Try this:
@
QList<QUrl> myList = fileUrlsVariant.value<QList<QUrl> >();
@ -
You are using wrong method for getting your list. Try this:
@
QList<QUrl> myList = fileUrlsVariant.value<QList<QUrl> >();
@
