[solved]QTcpServer can't catch the SIGNAL "newConnection"

BBFAG3

I run this TcpServer in a new thread, and I send a signal from main thread, it works.BUT! when a client connect to this server, the signal "newConnection" was not been called.

This is my code, thx a lot!

//main.cpp
@#include <QApplication>
#include"QThread"
#include"QObject"
#include"QTextStream"
#include"kserver.h"
#include"testclass.h"
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
qDebug()<<"main thread:"<<QThread::currentThreadId();

QThread serverThread;
KServer server(&a);
testClass t;
server.moveToThread(&serverThread);

QObject::connect(&server.KLServer,SIGNAL(newConnection()),&server,SLOT(newConnect()));

QObject::connect(&t,SIGNAL(t()),&server,SLOT(newConnect()));
serverThread.start();

t.emits();//This is my test signal,this signal was work.

QTextStream cin(stdin);

QString iptCmd;
while(1)
{
    //qDebug()<<server.KLServer.isListening();
    cin>>iptCmd;
}
return a.exec&#40;&#41;;

}
@

//kerver.cpp
@#include "kserver.h"

#include"QDebug"
KServer::KServer(QApplication *myApp, QObject *parent) :
QObject(parent)
{
myApp->processEvents();//I saw a post on StackOverflow, he said this will make it work, but it doesn't....
KLServer.listen(QHostAddress::Any,9825);
qDebug()<<"Server Thread"<<QThread::currentThreadId();
qDebug()<<"listening";

}

void KServer::receiveMsg()
{
qDebug()<<"RM";
qDebug()<<QThread::currentThreadId();
}

void KServer::newConnect()//never step into this function..
{
qDebug()<<"Server Thread"<<QThread::currentThreadId();
}
@

"testClass" only have a signal "t()" and a function to emit the signal, other headers only use to declare.

Thanks a LOOOOOOT!!!!!!!

BBFAG3

BTW, I'm sure the client connect to the server successfully, because if I close server side before client side, it will notice:The remote host closed the connection

gyll

You have this:
@ while(1)
{
//qDebug()<<server.KLServer.isListening();
cin>>iptCmd;
}
return a.exec();@

This means your main application will never execute a.exec(), i.e. it will never enter the event loop

BBFAG3

[quote author="gyll" date="1392737140"]You have this:
@ while(1)
{
//qDebug()<<server.KLServer.isListening();
cin>>iptCmd;
}
return a.exec();@

This means your main application will never execute a.exec(), i.e. it will never enter the event loop[/quote]

Thanks a lot....I really make a stupid mistake.....

gyll

Just out of curiosity: what kind of app are you trying to build?

BBFAG3

[quote author="gyll" date="1392737657"]Just out of curiosity: what kind of app are you trying to build?[/quote]

Eh..A game's server side..

ankursaxena

Ok .. If your problem is solved.. then please tag it is as a [solved]