[solved] Roundup value to nearest 200

Hi,
I need to roundup a value which is always a positive integer. I have to round up it to the nearest 200.
Rules are; Value should be roundedup to nearest 200. (if 350 I need 400 and if 250 I need 200)
 Minimum value should be 200. (even 1 should give me 200)
Can anybody help me?
Thanks in advance.

use the modulo operator "%".
if the value returned by modulo is smaller than 100 (half of 200) subtract the modvalue from the current value, otherwise add (200moduloValue) to your current value.You just need a special case handling for 2)

ravenworx,
Thanks for replying.
I created below method. Can you check is it the best way for do that?
@void setLength(int l)
{
int minimum_length = 200;if(l<minimum_length) { l=minimum_length; } else { int mod_200 =l % 200 ; if(mod_200!=0) { l = (l/200 + qRound(mod_200/100))*200; } } d>length = l;
}@
Thanks again.

have you tested your method?!
Your method doesn't behave like you described it should be.
Neither did you implement what i suggested.Here is the working method:
@
int roundValue(int l)
{
const int mod = 200;if(l < mod) { l = mod; } else { int modVal = l % mod; if( modVal < (mod/2.0) ) l = modVal; else l += (modmodVal); } return l;
}
@ 
yes I tested it and it is working for me. :)
give minimum 200 and round value to nearest 200.